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Group by the dates to weeks

By : Abhishek Kumar
Date : October 18 2020, 06:10 AM
help you fix your problem I have time in ms in epoch format, I need to translate this into a date and group it by a week number. , Try using strftime method:
code :
from datetime import datetime as dt
x = 1557499095332
dt.fromtimestamp(x/1000).strftime("%A, %B %d, %Y %I:%M:%S")

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Number of Weeks between Parameter Dates - Group by Week - SQL

By : mingzz
Date : March 29 2020, 07:55 AM
To fix the issue you can do I have 2 parameter in my stored procedure @FromDate and @ToDate, I want to work out the number of weeks between @FromDate and @ToDate, @FromDate is always a Monday while @ToDate is always a Sunday but the dates could cover weeks, months etc. , If I've got it right:
code :
With T( Number ) as
    Select 0 as Number
        union all
    Select Number + 1
        from T
        where Number < DATEDIFF(WW, @FromDate, @ToDate)



Group by weeks and dates EF in descending order

By : Web-Developer
Date : March 29 2020, 07:55 AM
Does that help If you want to get a list of records that are group by week and each of the list sorted by date in descending order, you can try:
code :
POdateRecordsEntity.Where(p => p.PO == "Unpaid" 
                                && p.Date <= yourTime).
.GroupBy(x => new { x.Date.Year, x.Week} )
.toDictionary(x => x.key, x => x.OrderByDescending(t=>t.Date).toList());

Laravel 5.3: Best way to retrieve data between dates and group them in weeks?

By : Marius
Date : March 29 2020, 07:55 AM
Does that help Use Carbon. Assuming the Record model and created_at attribute:
code :
$records=Record::where('created_at', '<' ,Carbon\Carbon::now()->subWeeks(3))->get() ->groupBy(function($date) {
                return Carbon\Carbon::parse($date->created_at)->format('W');
foreach($records as $week=>$record)
   echo $week;   // gives week 1, week 2 , week 3..
   foreach($record as $r)
    echo $r;

Get data from mysql and group them in weeks and also display the dates

By : Sebastián Arrué
Date : March 29 2020, 07:55 AM
Hope this helps There is no simple function that will yield a week interval (or start/end date of a week) given a week number. You have to find these dates manually.
try this :
code :
'fields' => array(
    'WEEK(Order.created) AS WEEK',

    'DATE_ADD(Order.created, INTERVAL(1-DAYOFWEEK(Order.created)) DAY) AS week_start',
    'DATE_ADD(Order.created, INTERVAL(7-DAYOFWEEK(Order.created)) DAY) AS week_end',

    'sum(Order.sub_total)   AS total_sub_total',
    'sum(Order.tax)   AS total_tax',
    'sum(Order.restaurant_delivery_fee)   AS total_restaurant_delivery_fee'
'fields' => array(
    'WEEK(Order.created) AS WEEK',

    'MIN(Order.created) as week_start',
    'MAX(Order.created) as week_end',

    'sum(Order.sub_total)   AS total_sub_total',
    'sum(Order.tax)   AS total_tax',
    'sum(Order.restaurant_delivery_fee)   AS total_restaurant_delivery_fee'

MS Access query, how to use SQL to group single dates into weeks

By : WOC666
Date : October 07 2020, 07:00 AM
it should still fix some issue As the first and last week numbers cross calendar years, both year and week number must be included:
code :
Option Compare Database
Option Explicit

    Public Const MaxWeekValue           As Integer = 53
    Public Const MinWeekValue           As Integer = 1
    Public Const MaxMonthValue          As Integer = 12
    Public Const MinMonthValue          As Integer = 1

' Returns, for a date value, a formatted string expression with
' year and weeknumber according to ISO-8601.
' Optionally, a W is used as separator between the year and week parts.
' Typical usage:
'   FormatWeekIso8601(Date)
'   ->  2017-23
'   FormatWeekIso8601(Date, True)
'   ->  2017W23
' 2017-04-28. Gustav Brock, Cactus Data ApS, CPH.
Public Function FormatWeekIso8601( _
    ByVal Expression As Variant, _
    Optional ByVal WeekSeparator As Boolean) _
    As String

    Const Iso8601Separator  As String = "W"
    Const NeutralSeparator  As String = "-"

    Dim Result              As String

    Dim IsoYear As Integer
    Dim IsoWeek As Integer

    If IsDate(Expression) Then
        IsoWeek = Week(DateValue(Expression), IsoYear)
        Result = _
            VBA.Format(IsoYear, String(3, "0")) & _
            IIf(WeekSeparator, Iso8601Separator, NeutralSeparator) & _
            VBA.Format(IsoWeek, String(2, "0"))
    End If

    FormatWeekIso8601 = Result

End Function

' Returns the ISO 8601 week of a date.
' The related ISO year is returned by ref.
' 2016-01-06. Gustav Brock, Cactus Data ApS, CPH.
Public Function Week( _
    ByVal Date1 As Date, _
    Optional ByRef IsoYear As Integer) _
    As Integer

    Dim Month       As Integer
    Dim Interval    As String
    Dim Result      As Integer

    Interval = "ww"

    Month = VBA.Month(Date1)
    ' Initially, set the ISO year to the calendar year.
    IsoYear = VBA.Year(Date1)

    Result = DatePart(Interval, Date1, vbMonday, vbFirstFourDays)
    If Result = MaxWeekValue Then
        If DatePart(Interval, DateAdd(Interval, 1, Date1), vbMonday, vbFirstFourDays) = MinWeekValue Then
            ' OK. The next week is the first week of the following year.
            ' This is really the first week of the next ISO year.
            ' Correct for DatePart bug.
            Result = MinWeekValue
        End If
    End If

    ' Adjust year where week number belongs to next or previous year.
    If Month = MinMonthValue Then
        If Result >= MaxWeekValue - 1 Then
            ' This is an early date of January belonging to the last week of the previous ISO year.
            IsoYear = IsoYear - 1
        End If
    ElseIf Month = MaxMonthValue Then
        If Result = MinWeekValue Then
            ' This is a late date of December belonging to the first week of the next ISO year.
            IsoYear = IsoYear + 1
        End If
    End If

    ' IsoYear is returned by reference.
    Week = Result

End Function

DateAdd("d", 7 - Weekday([WorkDate], vbMonday), [WorkDate])
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