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Less - how to generate values in a loop

By : Huan nguyen kim
Date : October 18 2020, 06:10 PM
will be helpful for those in need You can use less lang merge function to aggregate shadow values from multiple properties into a comma separated list. No need to store all shadows into one variable.
code :
@min: 1;   // Min random number
@max: 100; // Max

// Generate single shadow with random position    
.random-shadow() {
  @x: `Math.floor(Math.random() * (@{max} - @{min}))`;
  @y: `Math.floor(Math.random() * (@{max} - @{min}))`;
  box-shadow+: unit(@x, px) unit(@y, px) #fff;

// Loop to set @count shadows to the element
.multiple-shadow(@count) when (@count > 0) {
  .multiple-shadow(@count - 1);

a {
a {
  box-shadow: 79px 81px #fff, 76px 98px #fff, 67px 97px #fff, 44px 25px #fff, 54px 11px #fff;

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Need to generate an json array, then loop through the values

By : Tim
Date : March 29 2020, 07:55 AM
help you fix your problem Note that someArray is a misnomer as it is actually an Object. To loop through it, though:
code :
for(key in someArray) {
    "100": -1,
    "1001": 1,
    "102": 1,
    "103": -1 

How to generate an array with random values, without using a loop?

By : user2425935
Date : March 29 2020, 07:55 AM
wish helps you How can I generate an array in Perl with 100 random values, without using a loop?
code :
my @rand = map { rand } ( 1..100 );

run loop to generate values that increment intermittently in R

By : Casper Valdez
Date : March 29 2020, 07:55 AM
seems to work fine I am trying to label a sequence for contiguity. The values are already sorted. Now if the values in Tdiff are <400, its part of sequence "n". If the value of Tdiff suddenly changes to something >=400, it becomes part of a new sequence, say "n+1". , Does this do what you want?
code :
data$seq = cumsum(data$Tdiff >= 400)+1;

generate sets of normal distribution values within for loop

By : Rakesh Gajjar
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I think you are confused about what your loop is actually doing. It reassigns a newly allocated random vector to your variable e 500 consecutive times. This means that every iteration e is overwritten with a new random vector. Hence, after the loop is finished you end up with one random vector that is now assigned to e. You are basically just defining e in a very inefficient way :)
I assume, what you want to do is most likely something like this:
code :
nrSamples = 500
e <- list(mode="vector",length=nrSamples)
for (i in 1:nrSamples) {
  e[[i]] <- rnorm(n = 20, mean = 0, sd = 4)
> vector_1 <- e[[1]]
> vector_7 <- e[[7]]
> vector_1
 [1]  3.8713046  3.4672930  4.2840856  4.0388847 -3.0535864 -4.1402421 -2.7912700 -1.2332116  3.2628433  3.5377208
[11] -1.0929493  0.6466984 -5.5490625 -7.3033997  1.0898727  0.2001674  2.2646435  0.1623863  2.2611607 -1.1867225
> vector_7
 [1]  0.8199701 -3.1517209 -1.1319827  6.3150359 -3.7589505  1.4065123 -0.5410125 -3.0186291  6.6353592 -0.5002009
[11] -3.7416365  5.5324850 -2.2105955 -1.0931199 -2.0189795 -5.4934535  2.4210809  1.0956980 -7.6284702 -1.3574990
> vector_7[[3]]
[1] -1.131983
> # OR
> e[[7]][[3]]
[1] -1.131983

How to loop in a table to generate sheet from each row values in VBA

By : Christopher Frazier
Date : March 29 2020, 07:55 AM
it helps some times I'm new to the world of VBA, but I know we can do that. From a table containing X (variable) Row and AN (40) Columns (image 1), I want to populate cells in other worksheet (image 2 and 3) according to cells in a single line. , This should work as a beginning:
code :
Function LastWorksheet() As Worksheet
    Set LastWorksheet = Worksheets(Worksheets.Count)
End Function

Sub Main()
    Dim data() As Variant
    data = Worksheets("Sheet1").UsedRange.Value

    Dim wks As Worksheet
    Dim row As Integer, col As Integer
    For row = 1 To UBound(data)
        Set wks = Worksheets.Add(After:=LastWorksheet)
        wks.Name = "Output " & row
        wks.Cells(1, 1) = "What is the title?"
        wks.Cells(2, 1) = data(row, 1)
        wks.Cells(4, 1) = "What is the description?"
        wks.Cells(5, 1) = data(row, 2)
        wks.Cells(7, 1) = "What is the color?"
        wks.Cells(8, 1) = data(row, 3)
End Sub
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