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Same package name on different files


By : Elton peter
Date : October 18 2020, 06:10 PM
around this issue Can the function defined in the file b.go access a.go without importing anything? yes
What can be the reasoning behind dividing the code into two different files? This is just a structuring mechanism, for example when the file would become too large otherwise.
code :


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How do I automatically convert all javadoc package.html files into package-info.java files?


By : user2675607
Date : March 29 2020, 07:55 AM
Hope this helps You may need to change the directory separator if you're not running windows. Also, the conversion is a bit of a hack, but it should work. Out of curiosity, how many packages do you have that manual isn't an option?
code :
public class Converter {

    public static void main(String[] args) {
        File rootDir = new File(".");
        renamePackageToPackageInfo(rootDir);
    }

    private static void renamePackageToPackageInfo(File dir) {
        File[] files = dir.listFiles(new FilenameFilter() {
            @Override
            public boolean accept(File dir, String name) {
                return "package.html".equals(name);
            }
        });
        for (File file : files) {
            convertFile(file);
        }
        // now recursively rename all the child directories.
        File[] dirs = dir.listFiles(new FileFilter() {
            @Override
            public boolean accept(File pathname) {
                return pathname.isDirectory();
            }
        });
        for (File subdir : dirs) {
            renamePackageToPackageInfo(subdir);
        }
    }

    private static void convertFile(File html) {
        // determine the FQN package name
        String fqpn = getPackageName(html);

        // check if package-info.java already exists
        File packageInfo = new File(html.getParent(), "package-info.java");
        if (packageInfo.exists()) {
            System.out.println("package-info.java already exists for package: "+fqpn);
            return; 
        }

        // create the i/o streams, and start pumping the data
        try {
            PrintWriter out = new PrintWriter(packageInfo);
            BufferedReader in = new BufferedReader(new FileReader(html));
            out.println("/**");

            // skip over the headers
            while (true) {
                String line = in.readLine();
                if (line.equalsIgnoreCase("<BODY>"))
                    break;
            }
            // now pump the file into the package-info.java file
            while (true) {
                String line = in.readLine();
                if (line.equalsIgnoreCase("</BODY>"))
                    break;
                out.println(" * " + line);
            }

            out.println("*/");
            out.println("package "+fqpn+";");
            out.close();
            in.close();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        // queue the package.html file for deletion
        //html.deleteOnExit();
    }

    private static String getPackageName(File file) {
        StringBuilder path = new StringBuilder(file.getParent());
        // trim the first two characters (./ or .\)
        path.delete(0, 2);
        // then convert all separators into . (HACK: should use directory separator property)
        return path.toString().replaceAll("\\\\", ".");
    }

}

Package Acceptance Validation Error: Package contains multiple files with identical names


By : glassagencies
Date : March 29 2020, 07:55 AM
To fix the issue you can do After some investigation it seems the root cause of the problem can be found in WMAppManifest.xml file in Properties.
code :
<IconPath IsRelative="true" IsResource="false">Assets/ApplicationIcon.png</IconPath>
<SmallImageURI IsResource="false" IsRelative="true">Assets/Background.png</SmallImageURI>
<BackgroundImageURI IsResource="false" IsRelative="true">Assets/Background.png</BackgroundImageURI>
<IconPath IsRelative="true" IsResource="false">Assets\ApplicationIcon.png</IconPath>
<SmallImageURI IsResource="false" IsRelative="true">Assets\Background.png</SmallImageURI>
<BackgroundImageURI IsResource="false" IsRelative="true">Assets\Background.png</BackgroundImageURI>

The content folder in my nuget package isn't adding the files to the root when installing the package


By : 南安火车站酒店小姐
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The content subdirectory is only used for packages.config projects.
Projects using the PackageReference style of NuGet references use the contentFiles section instead which allows to specify the build action to use. Those files aren't copied to the project, but are included as items in the project and optionally set to copy to the consuming project's build output:
code :
<package>
  <metadata>
    ...
    <contentFiles>
        <files include="appsettings.json" buildAction="Content" copyToOutput="true" />
    </contentFiles>
  </metadata>
  <files>...</files>
</package>

Build a python package: how to call non code files in a package's main script


By : jrwh81
Date : March 29 2020, 07:55 AM
should help you out I think the problem is, that the path is interpreted relatively from where you are executing main.py Maybe this works:
code :
import os

this_path = os.path.dirname(__file__)
data =  pickle.load(open(
     os.path.join(this_path, 'data/data_1'),
    "rb"
))

How to specify the package name if multiple files exist in the package folder and one file contains the "package ma


By : Leonard
Date : March 29 2020, 07:55 AM
I wish this help you go files in the same package AKA folder must have the same package name. The only exception are tests that can have a _test extension. The rule is 1 folder , 1 package therefore the same package name for all go files in the same folder.
The answer is yes , move the "hello" package files to their own folder or , use the same package name for all files in the same directory.
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