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is there an way to ignore signals signature?

By : Pasha Gatilov
Date : October 18 2020, 06:10 PM
wish help you to fix your issue You should not use the same function for different types of callbacks. Some callbacks take different parameters, others have different return values — for instance, in your example, clicked does not return anything, whereas button-press-event returns a boolean value.
If you have common code that needs to be executed in different signal handlers, write a function and then call it from the various handlers.
code :

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Is it possible to ignore all signals?

By : Shine Standard
Date : March 29 2020, 07:55 AM
With these it helps I have a server application which I want to protect from being stopped by any signal which I can ignore. Is there a way to ignore all possible signals at once, without setting them one by one? , Yes:
code :
#include <signal.h>

sigset_t mask;
sigprocmask(SIG_SETMASK, &mask, NULL);

pthreads conditional - it is possible to ignore cond signals?

By : user4908454
Date : March 29 2020, 07:55 AM
hop of those help? The problem with your code is that the producer can acquire the mutex before any or all of the consumers, in which case the consumer(s) will be waiting at the pthread_mutex_lock(); when the condition is signalled - so they will then wait forever at the pthread_cond_wait() (signals aren't queued: if you aren't waiting when the condition variable gets signalled, you'll miss it).
This is why pthread condition variable must be paired with a condition over some shared state - called a predicate. Instead of just calling pthread_cond_wait(), you call it in a loop that tests the predicate:
code :
while (!new_value_available)
    pthread_cond_wait (&cond_producer_is_ready, &mu);
while (last_value_consumed == last_value_produced)
    pthread_cond_wait(&cond_producer_is_ready, &mu);

Bash have wait ignore signals

By : Olivier GEORGET
Date : March 29 2020, 07:55 AM
it should still fix some issue Call wait in a loop, and continue if wait exits with status 158 (indicating it was interrupted by SIGUSR1):
code :
sigusr1_no=30  # Mac OS X
# sigusr1_no=10  # Linux
trap 'sigHandle' SIGUSR1
sleep 12345 &
while :; do
    if [[ $status = $((sigusr1_no + 128)) ]]; then
        echo "USR1 handled, continuing"

Emit new style PyQt signals with arbitrary signature

By : Мано Безымянный
Date : March 29 2020, 07:55 AM
wish help you to fix your issue The new-style signal and slot syntax requires that signals are pre-defined as class attributes on a class that inherits from QObject. When the class is instantiated, a bound-signal object is automatically created for the instance. The bound-signal object has connect/disconnect/emit methods, and a __getitem__ syntax which allows different overloads to be selected.
Since bound-signals are objects, it no longer makes sense to allow the dynamic emission of arbitrary signals that was possible with the old-style syntax. This is simply because an arbitrary signal (i.e. one that is not pre-defined) could not have a corresponding bound-signal object for slots to connect to.
code :
class CallbackQueueToSignal(QtCore.QThread):
    dataSignal = QtCore.pyqtSignal([], [object], [object, object])   

    def _emit(self, signal, *args):
        getattr(self, signal)[(object,) * len(args)].emit(*args)

    def run(self):
        while True:
            args = self.queue.get()

class WorkerProcess(Process):

    def emit_to_mother(self, *args):

    def text_upper(self, text):
        self.emit_to_mother('dataSignal', (text.upper(),))

class MainWin(QtGui.QMainWindow):
    def __init__(self, parent=None):


Is there a way in Reactor to ignore error signals?

By : Tapan Soni
Date : March 29 2020, 07:55 AM
Any of those help since you are already processing urls in a flatmap, use onErrorResume(e -> Mono.empty()). this will let flatmap ignore the error. edit: within the flatmap, on the right hand side of the lambda
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