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as_tibble only returns a single variable


By : hsig
Date : October 18 2020, 06:10 PM
Any of those help The first arguments of as.data.frame must be a list of objects you wish to concatenate into a data frame, because the second argument is looking for the row.names. So to avoid confusing R into thinking that your second data frame are the row.names, and since you want to join vectors, put them all in a cbind()
code :
level_unhappy <- as.data.frame(cbind(brfss2013$qlmentl2, brfss2013$misdeprd, brfss2013$misnowork))
level_unhappy <- data.frame(brfss2013$qlmentl2, brfss2013$misdeprd, brfss2013$misnowork)


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Unexpected multiple returns in Python 3 for single variable


By : nguoiaoden
Date : March 29 2020, 07:55 AM
To fix this issue Your function is not returning anything; it is calling the question function again and again, but ignores the return value:
code :
def month_check(month):
    if month < 1:
        print("The month must be a number between 01 and 12. Please re-enter")
        month_q()
    elif month > 12:
        print("The month must be a number between 01 and 12. Please re-enter")
        month_q()
    else:
        print("Month_check returning month:", month)
        return month
month_q():
    What was the month [MM] which the installers were updated/created by xxx?:15
    month_check(15):
        The month must be a number between 01 and 12. Please re-enter
        month_q():
            What was the month [MM] which the installers were updated/created by xxx?:14
            month_check(15):
                The month must be a number between 01 and 12. Please re-enter
                month_q():
                    What was the month [MM] which the installers were updated/created by xxx?:13
                    month_check(13):
                        The month must be a number between 01 and 12. Please re-enter
                        month_q():
                            What was the month [MM] which the installers were updated/created by xxx?:12
                            month_check(12):
                                Month_check returning month: 12
                                <- 12
                            Month q returning: 12
                            <- 12
                        <- None
                    Month q returning: None
                    <- None
                <- None
            Month q returning: None
            <- None
        <- None
    Month q returning: None
    <- None
Update month: None
def month_q():
    while True:
        try:
            month = int(input('What was the month [MM] which the installers were  updated/created by xxx?:'))
            if not month_check(month):
                raise ValueError()
        except ValueError:
            print("Please re-enter a 2 digit month")
            continue
        print("Month q returning:", month)
        return month


# check the update month is a valid month
def month_check(month):
    if month < 1 or month > 12:
        print("The month must be a number between 01 and 12")
        return False
    return True
def month_q():
    while True:
        try:
            month = int(input('What was the month [MM] which the installers were  updated/created by xxx?:'))
            if month < 1 or month > 12:
                raise ValueError()
        except ValueError:
            print("Please re-enter a 2 digit month between 01 and 12.")
            continue
        print("Month q returning:", month)
        return month

Conditional returns or single variable return


By : Eric Ojeda
Date : March 29 2020, 07:55 AM
I hope this helps you . The following is a definition of the return statement.

Can I use single variable for method that returns 2 parameters


By : Andrey Samarin
Date : March 29 2020, 07:55 AM
To fix this issue The number of operands on the left side of the assignment must match the number of values returned by the function.
You can use the blank identifier to ignore a return value:
code :
resp, _ := http.Get("http://www.google.com/")

as_tibble control level of flattening


By : Ťįếň Đạţ
Date : March 29 2020, 07:55 AM
this one helps. as.tibble will repeat each column recycle each column value till they all have a shared number of elements. Here you are a and b have length 1, but c has length 2. So it seems you really want to treat it as a length one list, you just need to nest it in a list. I think this will do what you want in this case at least.
code :
parsed <- as_tibble(modify_if(x, ~length(.x)>1, list))

Why does as_tibble() round floats to the nearest integer?


By : RayGrund
Date : March 29 2020, 07:55 AM
may help you . This is not a rounding, it's only a way for {tibble} to display data in a pretty way:
code :
> mtcars %>% 
+   aggregate(disp ~ cyl, data=., mean) %>% 
+   as_tibble() %>% 
+   pull(disp)
[1] 105.1364 183.3143 353.1000
> mtcars %>% 
+   aggregate(disp ~ cyl, data=., mean) %>% 
+   as_tibble() %>% 
+   as.data.frame()
  cyl     disp
1   4 105.1364
2   6 183.3143
3   8 353.1000
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