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String concatenation: binary syntax v. operator <>


By : Sam Iezzi
Date : October 18 2020, 06:10 PM
will be helpful for those in need
Yes. The <>/2 operator is a macro that transforms the code into the <<>> special form.
code :
quote do str1 <> str2 end
|> Macro.expand(__ENV__)
|> Macro.to_string()
"<<str1::binary, str2::binary>>"


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Why is the php string concatenation operator a dot (.)?


By : Oceanfax Oceanx
Date : March 29 2020, 07:55 AM
it should still fix some issue I think it is a good idea to have a different operator, because dot and plus do completely different things.
What does "a string" + "another string"; actually mean, from a non specific language point of view?
code :
$myvar = 1;
$myvar2 = 2;

// would we expect a concatenation or addition?
$concat = $myvar + $myvar2;

String concatenation operator


By : nsmario
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further there is a lot of optimization done at compile time. So if you look at the de-compiled code after compilation you'll see like :
code :
    String s1 = "Hello World";
    String s6 = "Hello World";
    String s7 = "Hello";
    String s8 = " World";
    String s9 = (new StringBuilder(String.valueOf(s7))).append(s8).toString();
    String s10 = (new StringBuilder(String.valueOf(s7))).append(" World").toString();
    System.out.println(s1 == s6);
    System.out.println(s1 == s9);
    System.out.println(s1 == s10);
    System.out.println(s9 == s10);

String concatenation and + operator


By : user2734570
Date : March 29 2020, 07:55 AM
like below fixes the issue When you concatenate null by + operator, it is always converted to "null" String. This explains the first output Hellonull.
The concat function looks internally like this:
code :
public String concat(String s) {

    int i = s.length();
    if (i == 0) {
        return this;
    } else {
        char ac[] = new char[count + i];
        getChars(0, count, ac, 0);
        s.getChars(0, i, ac, count);
        return new String(0, count + i, ac);
    }
}

PHP syntax error for concatenation of string with the . operator


By : Joe Townson
Date : March 29 2020, 07:55 AM
it should still fix some issue I know its a silly question, but I can't get around with it, I am new to php: , try this query:
code :
$sqlCheckUser = "SELECT * FROM `user` where `email` = '".$email ."' OR `username` = '".$username ."'";

String concatenation using + operator


By : Akshay Bagule
Date : March 29 2020, 07:55 AM
will help you std::operator+ can be applied on std::string objects but not on char[]..
"Hello, " is a character array.
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