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How to split an array of arrays?


By : Ketul
Date : October 18 2020, 06:10 PM
This might help you You can use zip to separate letters from numbers and map to convert the tuples returned by zip to lists:
code :
array = [['a','1'], ['b','2'], ['c','3'], ['d','4'], ['e','5']]

letters, numbers = map(list, zip(*array))

print(letters)
print(numbers)
['a', 'b', 'c', 'd', 'e']
['1', '2', '3', '4', '5']


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Split an Array of arrays into 2 separate arrays in Ruby


By : John.J
Date : March 29 2020, 07:55 AM
should help you out Regardless of how you make the hash it will will have a Hash#keys method and a Hash#values. They both return arrays that are just what you seem to want.
code :
keys_array   = @level2.keys
values_array = @level2.values

Split Array within multiple Arrays in separate Arrays PHP


By : Pravin
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have an Array like this: , Try this
code :
foreach($unterp as $array) {
    echo("--");

    foreach($array as $values) {
        echo $values . '<input type="checkbox"/><br>';
    }
}

split one array into two parallel arrays OR read directly into two arrays in C#


By : yboutrou
Date : March 29 2020, 07:55 AM
Any of those help Its an interesting topic, usually homework is frowned upon, but I'll help point you in the right direction since you aren't asking outright for the code.
First, you want to get an array from a file, so you need to create a function that will do that and return to you an array. This makes your function prototype become
code :
public string[,] GetArrayFromFile(string fileName)
public string[,] GetArrayFromFile(string fileName)
{
    string[] fileData = File.ReadAllLines(fileName);
}
public string[,] GetArrayFromFile(string fileName)
{
    string[] fileData = File.ReadAllLines(fileName);

    string[,] result = new string[fileData.Length, 2];
}
public string[,] GetArrayFromFile(string fileName)
{
    string[] fileData = File.ReadAllLines(fileName);

    string[,] result = new string[fileData.Length, 2];

    for (int i = 0; i < fileData.Length;i++)
    {
        string[] parts = fileData[i].Split(',');
        result[i, 0] = parts[0];
        result[i, 1] = parts[1];  //Probably want to .Trim() here
    }

    return result;
}

How to split a multidimensional array of arrays into multiple single arrays in python?


By : Eswara moorthi
Date : March 29 2020, 07:55 AM
it helps some times How are you going to use variables with dynamic names? Don't do this. Chances are there are better ways to solve the problem. If you create dynamically named variables, you don't quite have a good handle to them.
You should use m_array directly.
code :
In [17]: [print(i) for i in m_array]
['x', 'y', 'x']
['a', 'b', 'c']
['1', '2', 3]

how to split numpy array and perform certain actions on split arrays [Python]


By : WhatsSingh
Date : March 29 2020, 07:55 AM
wish helps you Splitting as such won't be an efficient solution, instead we could reshape, which effectively creates subarrays as rows of a 2D array. These would be views into the input array, so no additional memory requirement there. Then, we would get argsort indices and select first five indices per row and finally sum those up for the desired output.
Thus, we would have an implementation like so -
code :
N = 512 # Number of elements in each split array
M = 5   # Number of elements in each subarray for sorting and summing

b = a.reshape(-1,N)
out = b[np.arange(b.shape[0])[:,None], b.argsort(1)[:,:M]].sum(1)
In [217]: a   # Input array
Out[217]: array([45, 19, 71, 53, 20, 33, 31, 20, 41, 19, 38, 31, 86, 34])

In [218]: N = 7 # 512 for original case, 7 for sample

In [219]: M = 5

# Reshape into M rows 2D array
In [220]: b = a.reshape(-1,N)

In [224]: b
Out[224]: 
array([[45, 19, 71, 53, 20, 33, 31],
       [20, 41, 19, 38, 31, 86, 34]])

# Get argsort indices per row
In [225]: b.argsort(1)
Out[225]: 
array([[1, 4, 6, 5, 0, 3, 2],
       [2, 0, 4, 6, 3, 1, 5]])

# Select first M ones
In [226]: b.argsort(1)[:,:M]
Out[226]: 
array([[1, 4, 6, 5, 0],
       [2, 0, 4, 6, 3]])

# Use fancy-indexing to select those M ones per row
In [227]: b[np.arange(b.shape[0])[:,None], b.argsort(1)[:,:M]]
Out[227]: 
array([[19, 20, 31, 33, 45],
       [19, 20, 31, 34, 38]])

# Finally sum along each row
In [228]: b[np.arange(b.shape[0])[:,None], b.argsort(1)[:,:M]].sum(1)
Out[228]: array([148, 142])
out = b[np.arange(b.shape[0])[:,None], np.argpartition(b,M,axis=1)[:,:M]].sum(1)
In [236]: a = np.random.randint(11,99,(512*512))

In [237]: N = 512

In [238]: M = 5

In [239]: b = a.reshape(-1,N)

In [240]: %timeit b[np.arange(b.shape[0])[:,None], b.argsort(1)[:,:M]].sum(1)
100 loops, best of 3: 14.2 ms per loop

In [241]: %timeit b[np.arange(b.shape[0])[:,None], \
                np.argpartition(b,M,axis=1)[:,:M]].sum(1)
100 loops, best of 3: 3.57 ms per loop
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