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Comparing list elements of two lists (with a twist)

By : mukesh shakya
Date : October 18 2020, 06:10 PM
should help you out You can use a list comprehension with zip, and take the abs of the difference between the elements in each tuple:
code :
[abs(i-j) for i,j in zip(l1,l2)]
['{0:.2f}%'.format((min(i,j)/max(i,j))*100) for i,j in zip(l1,l2)]
# [(8, 3), (5, 6), (2, 4), (1, 3)]
l1 = [8,5,2,1]
l2 = [3,6,4,3]

['{0:.2f}%'.format((min(i,j)/max(i,j))*100) for i,j in zip(l1,l2)]
# ['37.50%', '83.33%', '50.00%', '33.33%']

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Comparing 2 huge lists using C# multiple times (with a twist)

By : Are Jensen
Date : March 29 2020, 07:55 AM
I wish this helpful for you UPDATE
You can do a simple trick - group the prefixes by their first digits into a dictionary and match the numbers only against the correct subset. I tested it with the following two LINQ statements assuming every prefix has at least three digis.
code :
const Int32 minimumPrefixLength = 3;

var groupedPefixes = prefixes
    .GroupBy(p => p.Substring(0, minimumPrefixLength))
    .ToDictionary(g => g.Key, g => g);

var numberPrefixes = numbers
    .Select(n => groupedPefixes[n.Substring(0, minimumPrefixLength)]
     MPL    Runtime
     1     10.198 ms
     2      1.179 ms
     3        205 ms
     4        130 ms
     5        107 ms
List<String> prefixes = GeneratePrefixes();
List<String> numbers = GenerateNumbers(prefixes);
var numberPrefixes = numbers.Select(n => prefixes.First(n.StartsWith)).ToList();
using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;

namespace Test
    static class Program
        static void Main()
            // Set number of prefixes and calls to not more than 50 to get results
            // printed to the console.

            Console.Write("Generating prefixes");
            List<String> prefixes = Program.GeneratePrefixes(5, 10, 15);

            Console.Write("Generating calls");
            List<Call> calls = Program.GenerateCalls(prefixes, 5, 10, 50);

            Console.WriteLine("Processing started.");

            Stopwatch stopwatch = new Stopwatch();

            const Int32 minimumPrefixLength = 5;


            var groupedPefixes = prefixes
                .GroupBy(p => p.Substring(0, minimumPrefixLength))
                .ToDictionary(g => g.Key, g => g);

            var result = calls
                .GroupBy(c => groupedPefixes[c.Number.Substring(0, minimumPrefixLength)]
                .Select(g => new Call(g.Key, g.Sum(i => i.Duration)))


            Console.WriteLine("Processing finished.");

            if ((prefixes.Count <= 50) && (calls.Count <= 50))
                foreach (String prefix in prefixes.OrderBy(p => p))
                    Console.WriteLine(String.Format("  prefix={0}", prefix));

                foreach (Call call in calls.OrderBy(c => c.Number).ThenBy(c => c.Duration))
                    Console.WriteLine(String.Format("  number={0} duration={1}", call.Number, call.Duration));

                foreach (Call call in result.OrderBy(c => c.Number))
                    Console.WriteLine(String.Format("  prefix={0} accumulated duration={1}", call.Number, call.Duration));


        private static List<String> GeneratePrefixes(Int32 minimumLength, Int32 maximumLength, Int32 count)
            Random random = new Random();
            List<String> prefixes = new List<String>(count);
            StringBuilder stringBuilder = new StringBuilder(maximumLength);

            while (prefixes.Count < count)
                stringBuilder.Length = 0;

                for (int i = 0; i < random.Next(minimumLength, maximumLength + 1); i++)

                String prefix = stringBuilder.ToString();

                if (prefixes.Count % 1000 == 0)

                if (prefixes.All(p => !p.StartsWith(prefix) && !prefix.StartsWith(p)))

            return prefixes;

        private static List<Call> GenerateCalls(List<String> prefixes, Int32 minimumLength, Int32 maximumLength, Int32 count)
            Random random = new Random();
            List<Call> calls = new List<Call>(count);
            StringBuilder stringBuilder = new StringBuilder();

            while (calls.Count < count)
                stringBuilder.Length = 0;


                for (int i = 0; i < random.Next(minimumLength, maximumLength + 1); i++)

                if (calls.Count % 1000 == 0)

                calls.Add(new Call(stringBuilder.ToString(), random.Next(1000)));

            return calls;

        private class Call
            public Call (String number, Decimal duration)
                this.Number = number;
                this.Duration = duration;

            public String Number { get; private set; }
            public Decimal Duration { get; private set; }

Comparing lists of lists and writing certain elements into a new list

By : Marcos Santos
Date : March 29 2020, 07:55 AM
wish helps you It looks like this question has been asked dozens of times, but none of the answers have helped me out, so I'm afraid I'm asking it again (please don't hate me!). I have two lists of lists:
code :
s = set(x[0] for x in amm)
amv = [x for x in data if x[4] in s]

Comparing elements within list of lists

By : Ajith
Date : March 29 2020, 07:55 AM
around this issue You want to sum up the values at l[4] where key at l[3] is equal. The easiest way to do this is with defaultdict
Example code:
code :
from collections import defaultdict

d = defaultdict(float)

for nested in csv_list:
    d[nested[3]] += nested[4]

new_list = []
for x in d.items():
new_list = [list(x) for x in d.items()]

comparing elements in list of lists

By : user1752924
Date : March 29 2020, 07:55 AM
this will help As you question is a little unclear, try this and check is it ok or not.
code :
bad_list = []
for i,s in enumerate(l):
    if s[0] == l[i-1][0] or s[0] in bad_list:
        f = f + ' '.join(s[1:])
        f = f + ' '.join(s)
    f = f+ ' ;'
f = [f[:-1] + '.']

Removing sub list by comparing its elements with elements in all other sub lists in Python

By : user2564063
Date : March 29 2020, 07:55 AM
I wish this helpful for you With few adjustments in the initial code and after fixing the bug this code gives the correct output:
code :
lines=[[(x1, y1), (x2, y2), id1, id2],[(x2, y2), (x1, y1), id2, id1]]
for line in lines:
    if [line[1],line[0], line[3],line[2]] in lns: 
         lines.remove([line[1],line[0], line[3],line[2]]) 
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