To use strcpy or not

To use strcpy or not

By : Thomas Mockler
Date : October 20 2020, 06:10 AM
Does that help The assignment works without allocating any extra memory.
If you use strcpy(), you have to assign enough memory to x[0] before you do the copy (strlen(q[0]) + 1 bytes minimum), and you have to ensure it is released at the appropriate time.
code :

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Implementing a new strcpy function redefines the library function strcpy?

Implementing a new strcpy function redefines the library function strcpy?

By : Shin Yang
Date : March 29 2020, 07:55 AM
I wish did fix the issue. It is said that we can write multiple declarations but only one definition. Now if I implement my own strcpy function with the same prototype : , C11(ISO/IEC 9899:201x) §7.1.3 Reserved Identifiers
Multiple consecutive strcpy(), display contains bits of every next strcpy()

Multiple consecutive strcpy(), display contains bits of every next strcpy()

By : nutraherlean09
Date : November 02 2020, 03:01 PM
Does that help These 2 lines show what's going wrong:
Following line declares an array of char cP1_Move2_Name initialized with "POUND". The size of this array is exactly 6 bytes, that is the 5 characters from "POUND" plus one for the NUL terminator (strings are terminated by a NUL character, read the chapter dealing with string in your C textbook for more details):
code :
char cP1_Move2_Name[] = "POUND";
char cP1_Pokemon_Name[MAXSTRINGLENGTH] = "POKEMON";
char cP1_Move1_Name[MAXSTRINGLENGTH] = "TACKLE";
char cP1_Move2_Name[MAXSTRINGLENGTH] = "POUND";
Why can't I do strcpy?

Why can't I do strcpy?

By : svector
Date : March 29 2020, 07:55 AM
To fix the issue you can do , You are doing it wrong:
code :

int main() {
   const char* hello = "Hello, World!";
   char *str = malloc(strlen(hello)+1);

   printf("%s\n", str);
   return 0;
C - why is strcpy() necessary

C - why is strcpy() necessary

By : Kenneth Andersen
Date : March 29 2020, 07:55 AM
wish of those help Arrays in C are non-assignable and non-copy-initializable. That's just how arrays are in C. Historically, in value context (on the RHS of assignment) arrays decay to pointers, which is what formally prevents assignment and copy-initialization. This applies to all arrays, not only to char arrays.
C language inherits this arrays behavior from its predecessors - B and BCPL languages. In those languages arrays were represented by physical pointers. (And obviously re-assignment of pointers is not what you'd want to happen when you assign one array to another.) In C language arrays are not pointers, yet they do "simulate" the historical behavior of B and BCPL arrays by decaying to pointers in most cases. This historical legacy is what keeps C arrays non-copyable to this day.
Alternative to strcpy? or fix to strcpy in program?

Alternative to strcpy? or fix to strcpy in program?

By : user5348116
Date : March 29 2020, 07:55 AM
will help you I can't figure out what is wrong with this program. I have tried using , This statement
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