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Why does "int x = 5; printf("%d %d %d", x==5, x=10, x==5);" in C print "0 10 0"?


Why does "int x = 5; printf("%d %d %d", x==5, x=10, x==5);" in C print "0 10 0"?

By : Howie Wang
Date : October 20 2020, 06:10 AM
it should still fix some issue This is indeed undefined behavior. Arguments to functions are evaluated in an unspecified order, so doing anything that relies on that order becomes UB.
It looks like your compiler goes right-to-left (at least in this instance). That's a reasonable way to do it. But since it's UB, don't count on it always doing that.
code :


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Bizarre issue with printf in bash script:"09" and "08" are invalid numbers, "07" and "

Bizarre issue with printf in bash script:"09" and "08" are invalid numbers, "07" and "


By : Eric Lee
Date : March 29 2020, 07:55 AM
To fix this issue This is my bash script - I just want to left-pad a set of numbers with zeroes: , If you have your "09" in a variable, you can do
code :
a="09"
echo "$a"
echo "${a#0}"
printf "%04d" "${a#0}"
{"error":{"message":"Services require JSON-RPC","code":0,"origin":2},&

{"error":{"message":"Services require JSON-RPC","code":0,"origin":2},&


By : George F.
Date : March 29 2020, 07:55 AM
wish of those help JSON RPC expects the client to send parameters to the server using an HTTP POST command with the procedure parameters in the post data. When you type a URL into the browser it sends an HTTP GET command, which doesn't send any parameters.
RPC is intended for use by application programs, not directly by end users. See http://json-rpc.org/ for more details about it.
printf with "%d" of numbers starting with 0 (ex "0102") giving unexpected answer (ex '"66"

printf with "%d" of numbers starting with 0 (ex "0102") giving unexpected answer (ex '"66"


By : Janete Sales de Oliv
Date : March 29 2020, 07:55 AM
I hope this helps you . This is because when the first digit of a number (integer constant) is 0 (and second must not be x or X), the compiler interprets it as an octal number. Printing it with %d will give you a decimal value.
To print octal value you should use %o specifier
code :
   printf("%o", n);  
 12  125  3546  
 012 0125 03546  
 0xf 0xff 0X5fff   
Why is Aptana/Pydev showing "undefined variable" errors for "print" and "__name__" in my h

Why is Aptana/Pydev showing "undefined variable" errors for "print" and "__name__" in my h


By : user3532436
Date : March 29 2020, 07:55 AM
Hope this helps I think it's a bug of Aptana:
https://jira.appcelerator.org/browse/APSTUD-8098
php script returns value despite neither "echo" nor "print" nor "printf" is used?

php script returns value despite neither "echo" nor "print" nor "printf" is used?


By : ravitejs
Date : March 29 2020, 07:55 AM
help you fix your problem You are not setting CURLOPT_RETURNTRANSFER in your curl_setopt(). What that means is that when curl_exec() is called, the result of the cURL transfer is echoed out! That's where your returned data is coming from.
When CURLOPT_RETURNTRANSFER is TRUE, then curl_exec() returns the data and echos nothing. But, when CURLOPT_RETURNTRANSFER is FALSE (or unset), then curl_exec() echos the data and returns TRUE.
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