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Why do these two execvp produce different results?


Why do these two execvp produce different results?

By : Carl Christensen
Date : October 21 2020, 06:10 PM
seems to work fine As per execvp man
code :
int execvp(const char *file, char *const argv[]);


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Behaviour of a own haskell function: does sometimes stop to produce (easy to produce) results

Behaviour of a own haskell function: does sometimes stop to produce (easy to produce) results


By : user2939261
Date : March 29 2020, 07:55 AM
hop of those help? Even though you are using 64-bit integers, you still do not have enough capacity to store a temporary integer which is created in intLog:
code :
intLog base num =
    let searchExtend lower@(e, n) =
        let upper@(e', n') = (2 * e, n^2) -- this line is what causes the problems
    -- some code
    in (some if) searchExtend (1, base)
rawLists = recCall 1 threshould
threshould `quot` 1 -- same as threshould
intLog p remaining_threshould
intLog p threshould
searchExtend (e, n) = 
      let (e', n') = (2 * e, n ^ 2)
(2 ^ 32 + 1) ^ 2 :: Int is 8589934593
(2 ^ 32 + 1) ^ 2 :: Integer is 18446744082299486209
Why can't I see the results of execvp() on the command line?

Why can't I see the results of execvp() on the command line?


By : ThAtGuY7326
Date : March 29 2020, 07:55 AM
Hope this helps getcmd() misses to initialise line. It should initially point to NULL:
code :
char *line = NULL;
char * args[20];
for (size_t i = 0; i < 20; ++i)
{
  args[i] = NULL;
}
char * args[] = {
  "ls",
  "ls",
  "-alrt",
  NULL /* a must */
}
A way to call execl, execle, execlp, execv, execvP or execvp from Node.js

A way to call execl, execle, execlp, execv, execvP or execvp from Node.js


By : Rafael Augusto De Me
Date : March 29 2020, 07:55 AM
will be helpful for those in need I have created a module to invoke execvp function from NodeJS: https://github.com/OrKoN/native-exec
It works like this:
code :
var exec = require('native-exec');

exec('ls', {
  newEnvKey: newEnvValue,
}, '-lsa'); // => the process is replaced with ls, which runs and exits
Pyspark: writing results of UDF iteratively back to dataframe does not produce expected results

Pyspark: writing results of UDF iteratively back to dataframe does not produce expected results


By : Jérémy Noverraz
Date : March 29 2020, 07:55 AM
I wish this help you From what I have understood looking at your codes is that your next column value depends on the previous one. If my understanding is correct then I can tell that your udf function definition is placed at wrong place. And you need minor changes in your codes to make it work.
Lets go step by step
code :
+---+---+---+
|  a|  b|  c|
+---+---+---+
|  2| 12|  5|
|  8|  5|  7|
|  9|  4|  3|
|  3|  8|  2|
+---+---+---+
from pyspark.sql import functions as F
from pyspark.sql import types as T

df=df.withColumn('temp0', F.lit(0))
+---+---+---+-----+
|  a|  b|  c|temp0|
+---+---+---+-----+
|  2| 12|  5|    0|
|  8|  5|  7|    0|
|  9|  4|  3|    0|
|  3|  8|  2|    0|
+---+---+---+-----+
def func(p, end):
    start = 0
    s = 0
    pt = 0
    if p==1:
        pass
    elif p >1:
        start = end
        s=2
        pt =4
    end = start + pt - s
    return end

func_udf=F.udf(func, T.IntegerType())
def get_temp(df):
    l=['temp1','temp2','temp3']
    for p in xrange(1,4):
        df=df.withColumn(l[p-1],func_udf(F.lit(p), F.col('temp'+str(p-1))))
    return df

df=get_temp(df)
df=df.drop('temp0')
+---+---+---+-----+-----+-----+
|  a|  b|  c|temp1|temp2|temp3|
+---+---+---+-----+-----+-----+
|  2| 12|  5|    0|    2|    4|
|  8|  5|  7|    0|    2|    4|
|  9|  4|  3|    0|    2|    4|
|  3|  8|  2|    0|    2|    4|
+---+---+---+-----+-----+-----+
Postgres - only return results of query if two sub-queries produce results

Postgres - only return results of query if two sub-queries produce results


By : user2893832
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Here is a table called fruits: , Use two checks in the where clause:
code :
select *
from fruits
where fruit_name in ('banana', 'pear')
and exists (
    select from fruits
    where fruit_name = 'banana')
and exists (
    select from fruits
    where fruit_name = 'pear');
...
and exists (
    select id from fruits
    where fruit_name = 'banana')
...
with results as (
    select *
    from fruits
    where fruit_name in ('banana', 'pear')
)
select *
from results
where (
    select count(distinct fruit_name)
    from results
    ) = 2
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