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I am trying to store value in long long int type but giving wrong return


I am trying to store value in long long int type but giving wrong return

By : Athena
Date : October 22 2020, 06:10 PM
around this issue The largest possible value for a 64 bit long long int is 9,223,372,036,854,775,807. Your number is bigger than that. (Note that this number less the one you get is one off the number you actually want - that's not a coincidence but a property of 2's complement arithmetic).
It would fit in an unsigned long long int, but if you need an unsigned type you'll need to use a large number library for your number, or int128_t if your compiler supports it.
code :


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Abbreviated type name long long vs long long int, is it standard-compliant?

Abbreviated type name long long vs long long int, is it standard-compliant?


By : shuki
Date : March 29 2020, 07:55 AM
like below fixes the issue Yes, this is valid it is covered in the draft C++11 standard section 7.1.6.2 Simple type specifiers which says:
code :
long long      “long long int”
short          “short int”
CUDA texture can't return value type of unsigned long long

CUDA texture can't return value type of unsigned long long


By : user3358024
Date : March 29 2020, 07:55 AM
Does that help Below is a worked example that demonstrates the storing of data of type long long int in a 2D texture of type int2, then how to retrieve it via tex2D() and re-interpret it as long long int.
code :
#include <stdlib.h>
#include <stdio.h>

// Macro to catch CUDA errors in CUDA runtime calls
#define CUDA_SAFE_CALL(call)                                          \
do {                                                                  \
    cudaError_t err = call;                                           \
    if (cudaSuccess != err) {                                         \
        fprintf (stderr, "Cuda error in file '%s' in line %i : %s.\n",\
                 __FILE__, __LINE__, cudaGetErrorString(err) );       \
        exit(EXIT_FAILURE);                                           \
    }                                                                 \
} while (0)
// Macro to catch CUDA errors in kernel launches
#define CHECK_LAUNCH_ERROR()                                          \
do {                                                                  \
    /* Check synchronous errors, i.e. pre-launch */                   \
    cudaError_t err = cudaGetLastError();                             \
    if (cudaSuccess != err) {                                         \
        fprintf (stderr, "Cuda error in file '%s' in line %i : %s.\n",\
                 __FILE__, __LINE__, cudaGetErrorString(err) );       \
        exit(EXIT_FAILURE);                                           \
    }                                                                 \
    /* Check asynchronous errors, i.e. kernel failed (ULF) */         \
    err = cudaThreadSynchronize();                                    \
    if (cudaSuccess != err) {                                         \
        fprintf (stderr, "Cuda error in file '%s' in line %i : %s.\n",\
                 __FILE__, __LINE__, cudaGetErrorString( err) );      \
        exit(EXIT_FAILURE);                                           \
    }                                                                 \
} while (0)

__forceinline__ __device__ long long int int2_as_longlong (int2 a)
{
    long long int res;
    asm ("mov.b64 %0, {%1,%2};" : "=l"(res) : "r"(a.x), "r"(a.y));
    return res;
}

texture<int2, 2, cudaReadModeElementType> tex;

__global__ void kernel (int m, int n) 
{
    int2 data;
    for (int row = 0; row < m; row++) {
        for (int col = 0; col < n; col++) {
            data = tex2D (tex, col, row);
            printf ("% 11lld  ", int2_as_longlong (data));
        }
        printf ("\n");
    }
}

int main (void)
{
    int m = 4; // height = #rows
    int n = 3; // width  = #columns
    size_t pitch, tex_ofs;
    unsigned long long int arr[4][3]= 
        {{11111111LL, 11112222LL, 11113333LL},
         {22221111LL, 22222222LL, 22223333LL},
         {33331111LL, 33332222LL, 33333333LL},
         {44441111LL, 44442222LL, 44443333LL}};
    int2 *arr_d = 0;

    CUDA_SAFE_CALL(cudaMallocPitch((void**)&arr_d,&pitch,n*sizeof(*arr_d),m));
    CUDA_SAFE_CALL(cudaMemcpy2D(arr_d, pitch, arr, n*sizeof(arr[0][0]),
                                n*sizeof(arr[0][0]),m,cudaMemcpyHostToDevice));
    CUDA_SAFE_CALL (cudaBindTexture2D (&tex_ofs, &tex, arr_d, &tex.channelDesc,
                                       n, m, pitch));
    if (tex_ofs !=0) {
        printf ("tex_ofs = %zu\n", tex_ofs);
        return EXIT_FAILURE;
    }
    printf ("printing texture content\n");
    kernel<<<1,1>>>(m, n);
    CHECK_LAUNCH_ERROR();
    CUDA_SAFE_CALL (cudaUnbindTexture (tex));
    CUDA_SAFE_CALL (cudaFree (arr_d));
    return EXIT_SUCCESS;
}
How to assign starting address to an interator of a map<pair<long long int,long long int>,long long int >

How to assign starting address to an interator of a map<pair<long long int,long long int>,long long int >


By : Pasha
Date : March 29 2020, 07:55 AM
To fix the issue you can do I created a map of a pair and long long int - , The error tells you:
Is a function using template for data type not supposed to return long long int?

Is a function using template for data type not supposed to return long long int?


By : DiegoR
Date : March 29 2020, 07:55 AM
This might help you Template arguments are deduced from function arguments being passed (but not return type); so given pow(2, 50);, numeric_type is deduced as int.
You can specify numeric_type explicitly,
code :
auto powered = pow<long long int>(2, 50); // specify numeric_type as long long int explicitly
auto powered = pow(static_cast<long long int>(2), 50); // numeric_type is deduced as long long int
What does this scala error mean : "type mismatch; found : (((Long, Long), Long),) required: (((Long, Long), Long))

What does this scala error mean : "type mismatch; found : (((Long, Long), Long),) required: (((Long, Long), Long))


By : Влад Ковалёв
Date : March 29 2020, 07:55 AM
this will help You created outputTuples just fine, but you didn't create a function from output tuples to a string.
It says it wants type (((Long, Long), Long)) => String, which means it's a function taking ((Long, Long), Long) as an argument and producing a string. Here is one such function:
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