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Is there a way to get some function called on every thread that gets created?


Is there a way to get some function called on every thread that gets created?

By : CybersmithJK
Date : October 22 2020, 06:10 PM
help you fix your problem Not at the API level, however for your specific need on a termination handler you can install a top level exception handler which will terminate that specific thread once called (SetUnhandledExceptionFilter).
Windows installs this handler in each thread.
code :


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<BEA-050001> WLContext.close() was called in a different thread than the one in which it was created

<BEA-050001> WLContext.close() was called in a different thread than the one in which it was created


By : sanjay kumar
Date : March 29 2020, 07:55 AM
To fix the issue you can do WLContext.close() is probably not the real problem (it's even in some of the Oracle examples). What error messages do you see when deploy and undeploy are being called?
You should see something like:
code :
Deploying application from /tmp/something/myapp.ear
Current Status of your Deployment:
Deployment command type: deploy
Deployment State       : completed
Deployment Message     : no message
save()
status = activate(300000, "block='true'")
status.getStatusByServer()
status.getDetails()
# Get edit/lock for upcoming changes
edit()
startEdit(120000, 120000, 'false')
undeployApplication()
cd ('AppDeployments')
myapps=cmo.getAppDeployments()
for appName in myapps:
   try:
      appPath = "/AppDeployments/" + appName.getName()
      cd(appPath)
      print "Stopping deployment " + appName.getName()
      stopApplication(appName.getName())
      print "Undeploying " + appName.getName()
      undeploy(appName.getName(), timeout=60000)
   except Exception , e:
      print "Deployment " + appName.getName() + " removal failed."
Is dealloc guaranteed to be called on the same thread that created the object?

Is dealloc guaranteed to be called on the same thread that created the object?


By : Pothis Ram kumar Dha
Date : March 29 2020, 07:55 AM
hope this fix your issue The object is deallocated on whatever thread releases the last strong reference to it. That is, whatever thread calls -release the final time. It is actually during that -release call that the object is deallocated.
The documentation for the -release method in the NSObject protocol says:
Qt Slot is not called when it lives on a thread created via std::async

Qt Slot is not called when it lives on a thread created via std::async


By : Zakhar Sobarshov
Date : March 29 2020, 07:55 AM
this one helps. You need a running event loop in your thread, if you want to process cross-thread slot calls.
code :
auto future = QtConcurrent::run( [&myWidget](){
StartAndConnect(myWidget);
QEventLoop e;
e.exec();
});
How Can I Get an Event Handler to be Called From a Seperate Thread than the One it Was Created On?

How Can I Get an Event Handler to be Called From a Seperate Thread than the One it Was Created On?


By : user3766632
Date : March 29 2020, 07:55 AM
help you fix your problem An UI control has to be manipulated on the thread that it was created on (the UI thread). In order to achieve that, you'll have to 'invoke' the event-handler.
This can be done by raising the event like this:
infinite loop in a function called within a thread causes the thread to stay alive

infinite loop in a function called within a thread causes the thread to stay alive


By : Sachin Sreedharan
Date : March 29 2020, 07:55 AM
it should still fix some issue A thread getting interrupted doesn't stop it. It just causes the thread to get out of certain wait and sleep states. To have the thread exit an infinite loop based on input from another thread, put an explicit check against an Atomic<> in the loop and have the control thread modify the state of the atomic variable to where thread 'a' will exit the loop.
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