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uint8_t not rollover to 0 after reaching 255 not working properly


uint8_t not rollover to 0 after reaching 255 not working properly

By : Urim Vorfaj
Date : October 22 2020, 06:10 PM
With these it helps Because of the implicit promotions, ua84-1+20 will be an int and it will have the value 274. You should explicitely convert the result to uint8_t to have it to become 18.
printf does not come with enough magic to convert its arguments depending on the format(*). It only expects that it receives what it needs and just extract the passed parameters. So here you should write:
code :
    printf("ua81+1 = %" PRIu8 "\nua82-3 = %" PRIu8 "\nua83-4+7 = %" PRIu8 "\nua84-1+20 = %"
            PRIu8 "\n----------\n\n", (uint8_t)(ua81+1), (uint8_t)(ua82-3), (uint8_t)(ua83-4+7),
            (uint8_t)(ua84-1+20));


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Avoid casting from volatile static uint8_t to uint8_t in function calls?

Avoid casting from volatile static uint8_t to uint8_t in function calls?


By : Komb
Date : March 29 2020, 07:55 AM
around this issue I guess you are trying to pass a pointer to the variable and, while editing your question, you removed the pointer declaration in order to simplify, but that also changed your question. If you are passing a value to the function, there isn't any problem.
Now, if you are passing a pointer, the volatile modifier tells that the compiler should expect the value of the variable to change by means other than the compiled code. You really shouldn't pass a volatile variable as a non-volatile parameter to a function. The function itself must be changed to have the volatile parameter, and recompiled. Then function (with volatile parameter) is prepared to deal with a volatile variable.
Unable to convert a uint8_t vector iterator to a const uint8_t *

Unable to convert a uint8_t vector iterator to a const uint8_t *


By : Vitaly Sinyavsky
Date : March 29 2020, 07:55 AM
I wish this helpful for you When you use a std::vector you need to specify the type it holds. So your typedef needs to be:
code :
typedef std::vector<uint8_t> ClipboardDataVector;
void WriteToTempFile(const ClipboardDataVector& clipBoardData) {
   const uint8_t *data = clipBoardData.size() ? &clipBoardData[0] : NULL;
   // ...
}
Rollover menu displays properly in IE but not Firefox or Safari

Rollover menu displays properly in IE but not Firefox or Safari


By : Cheng Rongliang
Date : March 29 2020, 07:55 AM
may help you . I would strongly suggest that you stop using a table, and instead use DIV or SPAN tags, or a UL and LI construction.
Your problem is the display: inline; line. Inline elements have no size, so they ignore your width and height requirements. If you use the table, simply remove the line. If you use one of the others, consider using display: inline-block; instead?
Why does this specialized char_traits<uint8_t> and codecvt<uint8_t> for use with the basic_ifstream template

Why does this specialized char_traits<uint8_t> and codecvt<uint8_t> for use with the basic_ifstream template


By : Công nguyễn
Date : March 29 2020, 07:55 AM
I hope this helps you . I was able to reproduce a bad_cast on my gcc (4.7.2 on AIX).
The reason you got it is that gcc library implementors optimized basic_filebuf::xsgetn (which is called from basic_istream::read) to call plain C fread to read from the file if your stream's locale is non-converting (that is, you're not trying to read a UTF-8 or maybe GB18030 file into a UTF-32 string or something), which is absolutely the right thing to do. To find out if it is non-converting, it checks codecvt::always_noconv on the codecvt facet of the locale imbued in your stream... which doesn't exist.
code :
std::cout << std::use_facet<
                     std::codecvt<std::uint8_t, char, std::mbstate_t>
             >(stream.getloc()).always_noconv() << '\n';
stream.imbue(std::locale(stream.getloc(), 
             new std::codecvt<uint8_t, char, std::mbstate_t>));
Cannot properly create rollover on dynamically created html element

Cannot properly create rollover on dynamically created html element


By : user2108348
Date : March 29 2020, 07:55 AM
hope this fix your issue the code it's ok but when you use "loop_channel_name" take the last element of array. You must pass the actual element (this):
code :
 document.getElementById('channel_button_'+loop_channel_name).onmouseover = function(){

        alert('Rollover '+this.id);
    }
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