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Why does SIGINT stop sleep more than one time?


Why does SIGINT stop sleep more than one time?

By : Jask0
Date : October 23 2020, 06:10 PM
like below fixes the issue The SIGCHLD from the previous child-death-causing kill is arriving just when you're in the next sleep.
Sleep is an interruptible function. If a signal handler runs while your thread is in it, the sleep is going to abort. So then you proceed to the next kill, which is going to indirectly cause another SIGCHLD which will most likely happen when your next iteration's sleep, resulting in several skipped sleeps.
code :


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SDL/C++ OpenGL Program, how do I stop SDL from catching SIGINT

SDL/C++ OpenGL Program, how do I stop SDL from catching SIGINT


By : Duane
Date : March 29 2020, 07:55 AM
I hope this helps . Ctrl-C at the console generates an SDL_QUIT event. You can watch for this event using SDL_PollEvent or SDL_WaitEvent, and exit (cleanly) when it is detected.
Note that other actions can generate an SDL_QUIT event (e.g. attempting to close your main window via the window manager).
Not going to sleep after SIGINT in C

Not going to sleep after SIGINT in C


By : user3825623
Date : March 29 2020, 07:55 AM
Any of those help I have the following code. How to bring the control back to cleanupCode() when I received SIGINT while sleeping? I don't want to use goto or jump. Calling cleanupCode inside handler is not an option. , This works for me:
code :
#include <signal.h>
#include <stdio.h>
#include <unistd.h>

typedef struct sigaction SigAction;
static volatile sig_atomic_t loopFlag = 1;

static void sigHandler(int signum __attribute__((unused)))
{
    loopFlag = 0; 
}

static void cleanupCode(void) 
{
    printf("Graceful exit\n");
} 

static void setSignals(void)
{
    SigAction action;
    sigfillset(&action.sa_mask);
    action.sa_handler = sigHandler;
    action.sa_flags = 0;
    sigaction(SIGINT, &action, 0);
}

int main(void)
{    
    setSignals();
    while (loopFlag)
        sleep(600);
    cleanupCode(); 
    return(0);
}
Is there a way to stop time.sleep in windows?

Is there a way to stop time.sleep in windows?


By : user3866412
Date : March 29 2020, 07:55 AM
This might help you In *nix python signaling allows me to stop sleep before it is ready. Is there any similar mechanism available in windows -- seems that all the methods end up intercepting code only after the sleep? , The Python documentation for signal says:
code :
import signal, time

def handler(signum, frame):
    print('Signal handler called with signal', signum)

signal.signal(signal.SIGINT, handler)

print("signal set, sleeping")
time.sleep(10)
print("sleep done")
signal set, sleeping
Signal handler called with signal 2
sleep done
Does time.sleep() stop all executions?

Does time.sleep() stop all executions?


By : Ytembe Therese
Date : March 29 2020, 07:55 AM
With these it helps In my complex python program, when it's running, I have a piece of code that executes every 3 seconds that prints the program's progress as the percentage of the execution that's finished like so:
code :
from time import time

prev = time()
while True:
    now = time()
    if now - prev > 3:
        print 'report'
        prev = now
    else:
        pass
        # runs
Why does time.sleep() stop immediately when using signal handler?

Why does time.sleep() stop immediately when using signal handler?


By : Stephen Pratt
Date : March 29 2020, 07:55 AM
This might help you While doing some messing around with making a WSGI server, I noticed some test calls to time.sleep() inside a loop were only working the first iteration. Here's a reproduction: , from the linux sleep documentation
code :
import datetime
import time
def busy_sleep(seconds):
    start_time = datetime.datetime.now()
    seconds_slept = 0
    while seconds_slept < seconds:
        time.sleep(seconds - seconds_slept)
        seconds_slept = (datetime.datetime.now() - start_time).total_seconds()
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