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Return a literal string of a tuple in python


Return a literal string of a tuple in python

By : Joey Kim
Date : October 24 2020, 06:10 AM
Does that help Let's suppose I have a tuple , str(tup)
Read the Python docs, please.
code :


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Python Regex to Parse String and Return Tuple

Python Regex to Parse String and Return Tuple


By : user3156925
Date : March 29 2020, 07:55 AM
wish of those help I would use a single regular expression to match the entire line, with the parts I want in named groups ((?Pexampl*e)).
code :
import re
def extract_data2(s):
    pattern = re.compile(r"""\|\s*                 # opening bar and whitespace
                             '(?P<name>.*?)'       # quoted name
                             \s*\|\s*(?P<n1>.*?)   # whitespace, next bar, n1
                             \s*\|\s*(?P<n2>.*?)   # whitespace, next bar, n2
                             \s*\|""", re.VERBOSE)
    match = pattern.match(s)

    name = match.group("name")
    n1 = float(match.group("n1"))
    n2 = float(match.group("n2"))

    return (name, n1, n2)
Convert MySQLdb return from tuple to string in Python

Convert MySQLdb return from tuple to string in Python


By : sohel k
Date : March 29 2020, 07:55 AM
wish of those help If you're only going to be retrieving one value at a time (i.e. getting one column using cursor.fetchone()), then you can just change your code so that you get the first element in the tuple.
code :
Koc_pre = str(cursor.fetchone()[0]) 
Python: turning a tuple from return statement into a string

Python: turning a tuple from return statement into a string


By : Akmalhon Alixonov
Date : March 29 2020, 07:55 AM
help you fix your problem It's because you're using commas in your return statement, which Python is interpreting as a tuple. Try using format() instead:
code :
def wordCount(paragraph):
    splited = paragraph.split()
    wordnum = len(splited)
    eWord = []
    for aWord in splited:
        if "e" in aWord:
            eWord.append(aWord)
    eWordnum = len(eWord)
    percent = round(eWordnum / wordnum * 100,2)
    return "Your text contains {0} words, of which {1} ({2}%) contains an 'e'".format(wordnum, eWordnum, percent)
>>> wordCount("doodle bugs")

"Your text contains 2 words, of which 1 (0.0%) contains an 'e'"
Why does (function() { return this; }).call('string literal') return [String: 'string literal'] instead of 'string liter

Why does (function() { return this; }).call('string literal') return [String: 'string literal'] instead of 'string liter


By : Archiduque
Date : March 29 2020, 07:55 AM
To fix this issue .call internally invokes [[Call]], which performs
Perform OrdinaryCallBindThis(F, calleeContext, thisArgument).
code :
'use strict';
(function() {
  console.log(this);
  console.log(this === 'string literal');
}).call('string literal');
Using startswith against tuple, return matched string - Python

Using startswith against tuple, return matched string - Python


By : Neha Hunswadkar Sell
Date : October 06 2020, 06:00 AM
Hope that helps I'm using the startswith function in Python to clean up a passage of text. I have a list of 530k strings which represent a persons interpretation of a conversation, I'm trying to strip the first word out if it exists within a list. To do this I first need to identify that the string contains one of the items in the categories list (which is easy) but then I need to return the item from the categories list as well. , Using regex is one approach.
Ex:
code :
import re

s = 'item1: hello my name is roastbeeef'
categories = ['item1','item2','item3','item4','item5']
pattern = re.compile(r"(\b{}\b)".format("|".join(categories))) #--> (\bitem1|item2|item3|item4|item5\b) 
m = pattern.match(s)
if m:
    print(m.group(1))  # --> item1
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