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Why don't the values I type in the terminal match the values I've already stored in the array?


Why don't the values I type in the terminal match the values I've already stored in the array?

By : Matty Clark
Date : October 24 2020, 06:10 AM
it should still fix some issue I'm making a program that will let me read an integer entered at the terminal via the scanf function, and generate its assigned value from the array that has been created already. Here is the program's description: , This here is wrong:
code :
scanf("%d", array);
scanf("%d", &array[i]);
printf("%i weighs %dg\n", i, array[i]);
printf("The weight of this ingredient is: %d\n", ingredient[array]);


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Match words (regex) and create internal links from values stored in Array

Match words (regex) and create internal links from values stored in Array


By : allan conner
Date : March 29 2020, 07:55 AM
I want to compare 2 columns and mark the values that dont have a match

I want to compare 2 columns and mark the values that dont have a match


By : Miro Kvasnica
Date : March 29 2020, 07:55 AM
Any of those help My impression is you want to see all rows from DB_Total and include a calculated field which indicates whether a matching Name exists in TagNames_EA.
code :
SELECT
    d.Address,
    d.Type,
    d.Name,
    IIf(t.Name Is Null, False, True) AS match_found
FROM
    DB_Total AS d
    LEFT JOIN TagNames_EA AS t
    ON d.Name = t.Name;
Last number match dont show all values

Last number match dont show all values


By : Suthasinee
Date : March 29 2020, 07:55 AM
will help you right now I have this formula: , Perhaps the following:
code :
=IF(COUNTIF(A:A,A1)=COUNTIF($A$1:A1,A1),B1,"")
SQL If two column values dont match, then show all values that dont match

SQL If two column values dont match, then show all values that dont match


By : user2459721
Date : March 29 2020, 07:55 AM
it fixes the issue I have two tables joined up together I need to see if Product Code from table 1 (On the left) matches with the on on the right, based on their barcodes.. I have managed to inner join the barcodes and show only barcodes that match up. Just the prdouct code is the problem now... , Is this what you want?
code :
select t1.*
from table1 t1
where not exists (select 1
                  from table2 t2
                  where t2.code = t1.product_code and t2.barcode = t1.barcode
                 );
OCaml pattern matches values of type exp, but should match values of type 'a list

OCaml pattern matches values of type exp, but should match values of type 'a list


By : Ivan Boric
Date : March 29 2020, 07:55 AM
I wish did fix the issue. The line | []->[] in your pattern matching makes the compiler believe that e is a list. You should remove that line (why do you have it in the first place?).
This won't be enough to correct the problem, as you use that Node constructor that you didn't declare. You should change your declaration of tree.
code :
type tree = Node of string * exp * tree * tree
and exp = Etree of tree |  Int of int ;;
let t : exp = Etree( Node("a", Int 1, Empty, Empty) )
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