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Gremlin: select vertex based on comparison of two property values


Gremlin: select vertex based on comparison of two property values

By : zad zad
Date : October 24 2020, 06:10 PM
will be helpful for those in need Lets say I have the following Gremlin graph: , You can use where() step in this fashion:
code :
gremlin> g.addV('test1').property('pkey', 100).property('v1', 100).property('v2', 150)
==>v[0]
gremlin> g.addV('test1').property('pkey', 100).property('v1', 100).property('v2', 75)
==>v[4]
gremlin> g.V().hasLabel('test1').as('a').where('a',gt('a')).by('v1').by('v2')
==>v[4]
gremlin> g.V().hasLabel('test1').as('a').where(gt('a')).by('v1').by('v2')
==>v[4]


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CosmosDB Graph: How to update vertex having property with multiple values using gremlin?

CosmosDB Graph: How to update vertex having property with multiple values using gremlin?


By : Ibn Jalal
Date : March 29 2020, 07:55 AM
Does that help You're missing the list keyword that will allow you to add additional properties.
I'd recommend reading the Tinkerpop docs on VertexProperties
code :
g.V('john').property(list, 'country', 'USA')
   .property(list, 'country', 'India')
   .property(list, 'country', 'China')
CosmosDB Graph: How to update a value of property of vertex having multiple values using gremlin?

CosmosDB Graph: How to update a value of property of vertex having multiple values using gremlin?


By : Junior White
Date : March 29 2020, 07:55 AM
will be helpful for those in need Suppose my query is : , In a single query it's just that:
code :
g.V().has('id', 'john').
  sideEffect(properties('country').hasValue('India').drop()).
  property(list, 'country', 'China')
Gremlin group by vertex property and get sum other properties in the same vertex

Gremlin group by vertex property and get sum other properties in the same vertex


By : S. Buber
Date : March 29 2020, 07:55 AM
this one helps. We have vertex which will store various jobs and their types and counts as properties. I have to group by the status and their counts. I tried the following query which works for one property(receiveCount) , You could use cap() step just like:
code :
g.V().has("name","marko").out("knows").groupCount("a").by("name").group("b").by("name").by(values("age").sum()).cap("a","b")
 "data": [
      {
        "a": {
          "vadas": 1,
          "josh": 1
        },
        "b": {
          "vadas": [
            27.0
          ],
          "josh": [
            32.0
          ]
        }
      }
    ]
Gremlin - Store Vertex ID as property of another vertex

Gremlin - Store Vertex ID as property of another vertex


By : Daniel
Date : March 29 2020, 07:55 AM
this one helps. In gremlin is it possible to store a vertex ID inside another vertex? For instance if I created a vertex like this , You could do something like this
code :
gremlin> g.addV('x').property('otherid','3').iterate()

gremlin> g.V().hasLabel('x').as('a').V().where(eq('a')).by(id).by('otherid')
==>v[3]
Gremlin query to select vertex based on count of out edges on a particular subset of out vertex

Gremlin query to select vertex based on count of out edges on a particular subset of out vertex


By : user3335770
Date : March 29 2020, 07:55 AM
To fix the issue you can do For example, there are two types of vertex in Graph [ Account , User]. Account vertexes have edges to user vertex denoting a list of users form an Account vertex. User vertex has two property ( name, phoneNumber). I want to select accounts who are connected to more than 2 users whose name starts with foo. , This query would do it:
code :
g.V().hasLabel("Account")
.where(out().hasLabel("User")
.has("name", startingWith("foo"))
.count().is(gte(2)))
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