Passing variable into lambda

Passing variable into lambda

By : misty vera
Date : October 25 2020, 07:10 AM
help you fix your problem As Michael already pointed out, closures can not be converted to function pointers.
It might be better to accept templated argument or std::function instead of raw function pointer, if there is such an option.
code :

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Passing variable through lambda into functions Tkinter

Passing variable through lambda into functions Tkinter

By : shaik feroz
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , My problem with the following code is passing 'i' (just a simple range of numbers but changes according to number_boxes) through lambda to callback in order to have seperate functionality of each box created. , Your code is very close, however this line:
code :
self.box[i].bind("<Button-1>", lambda self, event,i : self.callback(event, data))
self.box[i].bind("<Button-1>", lambda event, index=i: self.callback(event, index))
# Create an empty list based on the number of boxes created 
# above. This could go in your class's __init__ function, 
# or it could be declared globally, depending on the scope
# of self.box and the loop which determines its length.
self.clicked = ([False] * len(self.box))

# Finally, in your callback, check one member of the list,
# depending on which box was clicked.
def cb(self, event, index):
    if not self.clicked[index]:
        self.box[index].delete(0, END)
        self.clicked[index] = True
    # Print the value of each of the widgets stored in the box list.
    for i, j in enumerate(self.box):
        print("%ith element: %s" % (i, j.get()))  
Passing a variable to a lambda-function

Passing a variable to a lambda-function

By : Adi
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , How to pass a variable "$field" to a lambda-function? , try
code :
array_map(function($item) use($field) { return $item[$field]; }, $array);
AWS API Gateway only passing 1st variable to function, but lambda test passes all

AWS API Gateway only passing 1st variable to function, but lambda test passes all

By : ninja camp
Date : March 29 2020, 07:55 AM
may help you . The issue was that the API gateway was passing in a number as a string. I had to fix the get method mapping template in integration request as follows
In order to pass variables from API Gateway to back-end as integers, the quotes around the variable values need to be removed. Please make sure the values are getting passed as an integer from the client otherwise you will get the same error that you mentioned in your initial correspondence. In this case, I update the body mapping template from:
code :
    "search_keyword" : "$input.params('search_keyword')",
    "page": "$input.params('page')",
    "RPP": "$input.params('RPP')"
    "search_keyword" : "$input.params('search_keyword')",
    "page": $input.params('page'),
    "RPP": $input.params('RPP')
Why does passing a variable to a lambda in Kotlin works?

Why does passing a variable to a lambda in Kotlin works?

By : user1693628
Date : March 29 2020, 07:55 AM
I hope this helps . In Kotlin, the last or the single expression in a lambda is the return value.
In the getNum { x } expression, { x } is a lambda with a single expression x in it, which is thus considered the return value, so when the lambda is invoked, it only evaluates x captured in the closure and returns its value back to getNum.
Passing variable to lambda function

Passing variable to lambda function

By : Dwul Gk
Date : March 29 2020, 07:55 AM
it fixes the issue I managed to get the next weekday from today by means of defining a function and passing it in a for loop (!). I'm sure there are far more pythonic ways to do this, which I would really appreciate to see.
code :
def next_weekday(weekday):
    todaydate = datetime.date.today()
    days_ahead = weekday - todaydate.weekday()
    if days_ahead <= 0: # Target day already happened this week
        days_ahead += 7
    return todaydate + datetime.timedelta(days_ahead)

for i in range(df_example.shape[0]):
    df_example.loc[i,'next_date'] = next_weekday(weekday=int(df_example.loc[i,'base_date_weekday']))
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