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Recursive and no-recursive get different answer


Recursive and no-recursive get different answer

By : Kaj
Date : October 25 2020, 07:10 AM
wish help you to fix your issue remain() must be defined as long long int. The way you have it you multiply two ints here and observe an integer overflow:
code :
else if(y%2==1) return ((remain(y-1))*(remain(1)))%d;
long long int remain(long long int y)


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I'm confused about what's recursive, tail recursive, primitive recursive and what's not

I'm confused about what's recursive, tail recursive, primitive recursive and what's not


By : Robosmith
Date : March 29 2020, 07:55 AM
wish helps you A function is recursive if it calls itself (not necessarily in every case, but at least in one case). For example:
code :
sum [] = 0
sum (x:xs) = x + sum xs
sum [] acc = acc
sum (x:xs) acc = sum xs (x + acc)
f = do
    x <- g
    h x
f = g >>= (\x -> h x)
javascript recursive function wrong answer

javascript recursive function wrong answer


By : Anjali Krishna
Date : March 29 2020, 07:55 AM
This might help you You are using a global variable in your recursive function, so it will be changed while you are using it.
Change this:
code :
a = []
var a = []
SQL Recursive CTE: preventing a recursive loop by multiple recursive references

SQL Recursive CTE: preventing a recursive loop by multiple recursive references


By : Hari
Date : March 29 2020, 07:55 AM
this will help The final version. Assuming '/' will never be part of the base or parent name.
code :
;with sample_data (Base, Parent) as (
    -- TEST 1
    --        select 'test1', 'test2'
    --union   select 'test2', 'test3'
    --union   select 'test3', 'test2'
    -- TEST 2
            select 'test1', 'test2'
    union   select 'test2', 'test3'
    union   select 'test3', 'test4'
    union   select 'test3', 'test9'
    union   select 'test4', 'test5'
    union   select 'test5', 'test3'
    union   select 'test9', 'test8'
    -- TEST 3
    --        select 'test1', 'test2'
    --union   select 'test2', 'test3'
    --union   select 'test3', 'test1'
    -- TEST 4
    --        select  'test1', 'test1'
    --union   select  'test1', 'test2'
),
nt_list (Base, Ancestor, [level], [path]) as (
        select  Base,
                Parent Ancestor,
                1 [level],
                '/' + convert(varchar(max), rtrim(Base)) + '/' [path]
        from    sample_data
        where   Base = 'test1' -- START HERE
        union all
        select  ntl.Base,
                nt.Parent,
                ntl.[level] + 1 [level],
                ntl.[path] + rtrim(nt.Base) + '/'
        from    nt_list ntl
        join    sample_data nt on ntl.Ancestor = nt.Base
        where   ntl.path not like '%/' + rtrim(nt.Parent) + '/%'
)
select  distinct
        ntl.Base,
        ntl.Ancestor
from    nt_list ntl
order by Ancestor
Recursive Knapsack returning wrong answer

Recursive Knapsack returning wrong answer


By : Daniel Nascimento
Date : March 29 2020, 07:55 AM
it fixes the issue The following code should be returning 16 as far as I can tell but for some reason, it returns 10. Does anyone know what my bug might be? Basically it's the Knapsack problem in Java and I've ran through the whole code on paper and it seems to return the right answer to me but I cannot figure out why when it's properly run, it returns back 10. , Your Stack is being modified across the calls. So a line like
code :
return Math.max(optimalValue(items,totalWeight), value + optimalValue(items, totalWeight-weight));
Why can't I get correct answer when I used recursive with Ruby?

Why can't I get correct answer when I used recursive with Ruby?


By : Sharmin
Date : March 29 2020, 07:55 AM
it fixes the issue I created a code snippet with Java like following. This is the code to get all combination from nCr. , In this part:
code :
for i in 0..n.size
    arr = n.dup
    arr.delete_at(i)
    combi(arr, r, ans)
end
for i in 0...n.size
    arr = n.dup
    arr.delete_at(i)
    combi(arr, r, ans)
end
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