How do I avoid constructors?

How do I avoid constructors?

By : Anne Caroline
Date : October 25 2020, 07:10 PM
Any of those help You cannot create an object without calling one of its constructors, so you likely want a no-argument constructor in your Cash class:
code :
public Cash() {


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How to avoid boilerplate code constructors?

How to avoid boilerplate code constructors?

By : Nicat
Date : March 29 2020, 07:55 AM
help you fix your problem In a C++11 compliant compiler (§12.9 in the standard), you can actually do this quite easily:
code :
struct Son : public Base {
  using Base::Base;
Why do I want to avoid non-default constructors in fragments?

Why do I want to avoid non-default constructors in fragments?

By : Ashish Yadav
Date : March 29 2020, 07:55 AM
wish of those help Make a bundle object and insert your data (in this example your Category object). Be careful, you can't pass this object directly into the bundle, unless it's serializable. I think it's better to build your object in the fragment, and put only an id or something else into bundle. This is the code to create and attach a bundle:
code :
Bundle args = new Bundle();
args.putLong("key", value);
Type value = getArguments().getType("key");
How to avoid making long constructors

How to avoid making long constructors

By : abhijitm
Date : March 29 2020, 07:55 AM
I hope this helps you . Do not use the builder pattern right away. It is not for types with tons of required fields. It's for types with tons of optional fields.
Builders' required properties are specified via the constructor. You are not forced to define values using methods, which makes those values optional.
code :
class DataResponseDetails {
    private boolean isLink;
    private String maskInfo;
    private TypeOfId idType;

    public DataResponseDetails(boolean isLink, String maskInfo, TypeOfId idType) {
class DataResponse {
    private DataResponseDetails details;
    private String response;

    public DataResponse(DataResponseDetails details, String response, ...) {
Avoid copying all constructors in subclasses

Avoid copying all constructors in subclasses

By : Dmitry Beketov
Date : March 29 2020, 07:55 AM
I hope this helps . You can accomplish this by inheriting constructors (since C++11).
code :
class Sub : public sf::Sprite {
        using sf::Sprite::Sprite;

        // My subclass specific code
How to avoid non-default constructors in fragments?

How to avoid non-default constructors in fragments?

By : Ruby Smith
Date : March 29 2020, 07:55 AM
With these it helps I'm currently working on an android app, and it suddenly gave me these errors (it used to work like this, which is the strange part): , You have to call fragment something like this:
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