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Problem with list value (ValueError) in python 3


Problem with list value (ValueError) in python 3

By : Chris Morris
Date : October 25 2020, 07:10 PM
it should still fix some issue I am trying to create a simple card game for school, I am at the stage of coding how gameplay works within the game and am getting a ValueError when trying to remove a value from a list
code :
list.remove(x)


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problem with closing python pypdf - writing. getting a valueError: I/O operation on closed file

problem with closing python pypdf - writing. getting a valueError: I/O operation on closed file


By : tos
Date : March 29 2020, 07:55 AM
may help you . OK, I found your problem. You were right to call file(). Don't try to call open() at all.
Your problem is the input file still needs to be open when you call self.pdfoutput.write(self._pdfstream), so you need to remove the line self._filestream.close().
code :
from pyPdf import PdfFileReader as PfR, PdfFileWriter as PfW

input_filename = 'in.PDF' # replace with a real file
output_filename = 'out.PDF' # something that doesn't exist

infile = file(input_filename, 'rb')
reader = PfR(infile)
writer = PfW()

writer.addPage(reader.getPage(0))
outfile = file(output_filename, 'wb')
writer.write(outfile)
print "First Write Successful!"
infile.close()
outfile.close()

infile = file(input_filename, 'rb')
reader = PfR(infile)
writer = PfW()

writer.addPage(reader.getPage(0))
outfile = file(output_filename, 'wb')
infile.close() # BAD!

writer.write(outfile)
print "You'll get an IOError Before this line"
outfile.close()
Python socket networking - ValueError: list.remove(x): x not in list

Python socket networking - ValueError: list.remove(x): x not in list


By : Shrek1412
Date : March 29 2020, 07:55 AM
will be helpful for those in need Check if the item you have exists in the list before attempting to remove or just use a try-except
code :
if item in lst:
    lst.remove(item)
else:
    pass # you may print some message or log something

# OR

try:
    lst.remove(item)
except ValueError:
    pass # you may print some message or log something
Python function: return list of lists, and simple list --> ValueError (too many values to unpack)

Python function: return list of lists, and simple list --> ValueError (too many values to unpack)


By : srikanth
Date : March 29 2020, 07:55 AM
should help you out I have a Python function ('extract features') that should return two elements. The first element is a list of lists: feat_values = [[a, b], [c, d], [e, f]]. The second element is a simple list: feat_names = [1, 2, 3]. , The call
code :
feat_values, feat_names = list(map(extract_features, train_data.data))
feat_values, feat_names = zip(*map(extract_features, train_data.data))
Python NeuroEvolutionProject: ValueError: list.remove(x): x not in list (when x is, in fact, in the list)

Python NeuroEvolutionProject: ValueError: list.remove(x): x not in list (when x is, in fact, in the list)


By : Phillip A. Mabrey
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Mutating a list that you are iterating over is a recipe for disaster. Consider the following simple case:
code :
entities = [1,2,3,4,5]
for entity in entities:
    entities.remove(entity)
print(entities)
to_remove = []
for entity in self.active:
    entity.updatePosition()
    #bla bla bla unimportant...
    if entity.goesOutOfBounds():
        to_remove.append(entity)
for entity in to_remove:
    self.active.remove(entity)
for entity in self.active[:]:
    entity.updatePosition()
    #bla bla bla unimportant...
    if entity.goesOutOfBounds():
        self.dead.append(entity)
        self.active.remove(entity)
Python gives ValueError: list.remove(x): x not in list when removing a tuple from list

Python gives ValueError: list.remove(x): x not in list when removing a tuple from list


By : cjhenders
Date : March 29 2020, 07:55 AM
may help you . Adapting my confirmed comment: filter returns all matches as a sequence, not just the first match, so "newtuple" is a misnomer here, it's really "newtuples" plural (a list of tuples on Py2, a generator of tuples on Py3).
The most straightforward fix is to change your code to:
code :
newtuples = filter(lambda x: x[2].startswith('902'), csvlist)
for newtuple in newtuples:  # in list(newtuples) on Py3 to avoid mutating csvlist while iterating
    csvlist.remove(newtuple)
csvlist[:] = [x for x in csvlist if x[2].startswith('902')]
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