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Compare every 1kb of contents of two files instead of character by character


Compare every 1kb of contents of two files instead of character by character

By : dvdalln02
Date : October 25 2020, 07:10 PM
this one helps. Read in chunks, so fread not getc.
Then compare in chunks, so strcmp (or memcmp) not char ==.
code :


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How do i compare two files character by character

How do i compare two files character by character


By : user3231137
Date : March 29 2020, 07:55 AM
To fix this issue You call char_cmp(fp1, fp2)) twice - once in the switch statement, and the second time in the default condition. The second time it returns you the second char position in which they differ (or something another, really unexpected :)
Change it to
code :
int k = char_cmp(fp1, fp2));
switch( k )
...
printf("files differ: char %d\n", k);
(c = fgetc(fp1)) == (d = fgetc(fp2))
(c = fgetc(fp1)) == (d = fgetc(fp2) && c != EOF
can't compare getchar != '/n' , get warning: multi-character character constant

can't compare getchar != '/n' , get warning: multi-character character constant


By : mr juno
Date : March 29 2020, 07:55 AM
wish help you to fix your issue '/n' is 2 characters I think you are looking for '\n'
Getchar() will get 1 char '/n' is 2 characters (and because you defined the characters already it is a constant) so it is a multiple character character constant
how to compare a string with items in a list , character by character in python

how to compare a string with items in a list , character by character in python


By : Gouri Nair
Date : March 29 2020, 07:55 AM
this will help I have a list and I want to compare user input with that list , but character by character. for example user can only input some character and leave the rest by dots. (for example : V...r..n ) How do I can compare strings character by character, and if it only includes all characters by user input (skip the dots) , You can use regular expressions:
code :
import re

list1 = ["Vaporeon", "Jolteon", "Flareon", "Espeon", "Umbreon", "Leafeon", "Glaceon", "Sylveon"]
s = input()  # for example "V...r..n"

re_s = re.compile(''.join('.' if ch == '.' else re.escape(ch) for ch in s) + '$')
for i in list1:
    if re_s.match(i):
        print(i)
from itertools import zip_longest

list1 = ["Vaporeon", "Jolteon", "Flareon", "Espeon", "Umbreon", "Leafeon", "Glaceon", "Sylveon"]
s = input()  # for example "V...r..n"
for i in list1:
    if all(c1 == c2 for c1, c2 in zip_longest(i, s) if c2 != '.'):
        print(i)
R: Compare character strings across multiple columns to character string in a single column by row

R: Compare character strings across multiple columns to character string in a single column by row


By : user3200868
Date : March 29 2020, 07:55 AM
Any of those help I am trying to create a variable that is a logical value when comparing one character string to more than two other character strings in a data.table and I need to ignore NA's. , How about the following
code :
setDT(D1)
D1[, Match := apply(sapply(.SD, `==`, D1[, "var1"]), 1, any), .SDcols = c("var2", "var3")]
D1
#ID  var1  var2  var3 Match
#1: a001 char1 char1 char1  TRUE
#2: a002 char1  <NA> char1  TRUE
#3: a003 char2 char1 char1 FALSE
setDT(D1)
D1[, Match := apply(sapply(.SD, `==`, D1[, "var1"]), 1, all, na.rm = T), .SDcols = c("var2", "var3")]
Read contents of a text file character by character into a vector without skipping whitespace or new lines

Read contents of a text file character by character into a vector without skipping whitespace or new lines


By : zihao_li
Date : March 29 2020, 07:55 AM
I hope this helps you . So I have several text files. I need to figure out the 10 most common characters and words in the file. I've decided to use a vector, and load it with each character from the file. However, it needs to include white space and new lines. , The problem with your code right now is that you're calling
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