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How can I add custom signs to spaCy's punctuation functionality?


How can I add custom signs to spaCy's punctuation functionality?

By : Joe Black
Date : October 25 2020, 07:10 PM
Any of those help You can do this by replacing the lex_attr_getters[IS_PUNCT] function by a custom one which holds a list of symbols describing the additional characters.
code :
import spacy
from spacy.symbols import IS_PUNCT
from spacy.lang.en import EnglishDefaults

def is_punct_custom(text):
    extra_punct = ["|"]
    if text in extra_punct:
        return True
    return is_punct_original(text)

# Keep a reference to the original is_punct function
is_punct_original = EnglishDefaults.lex_attr_getters[IS_PUNCT]
# Assign a new function for IS_PUNCT
EnglishDefaults.lex_attr_getters[IS_PUNCT] = is_punct_custom


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Lucene bigrams tokenizer to include punctuation signs

Lucene bigrams tokenizer to include punctuation signs


By : user3168730
Date : March 29 2020, 07:55 AM
Hope that helps You could create a ShingleAnalyzerWrapper that uses an analyzer based on LetterTokenizer. LetterTokenizer breaks the input text at non letters. Something like:
code :
public class MyCharAnalyzer extends Analyzer { 

  public TokenStream tokenStream(String fieldName, Reader reader) {
    TokenStream result = new LetterTokenizer(reader);    
    return result;
  }
}

ShingleAnalyzerWrapper myBigramWrapper = new ShingleAnalyzerWrapper(new MyCharAnalyzer());
Regex.Replace punctuation signs

Regex.Replace punctuation signs


By : Morten Knudsen
Date : March 29 2020, 07:55 AM
To fix this issue Your regular expression is invalid. You're replacing whole match with itself, and that's why you don't see any change in your result string.
Try that one:
code :
public class PunctionationSignsSpaceing
{
    private string _pattern;
    public PunctionationSignsSpaceing()
    {
        _pattern = " *([),!;?.]) *";
    }
    public string FormatString(string str)
    {
        str = Regex.Replace(
            str, _pattern, "$1 ",
            RegexOptions.Multiline | RegexOptions.Compiled
        );
        return str;
    }
}
public class PunctionationSignsSpaceing
{
    private string _pattern = " *([),!;?.]) *";

    public string FormatString(string str)
    {
        str = Regex.Replace(
            str, _pattern, "$1 ",
            RegexOptions.Multiline | RegexOptions.Compiled
        );
        return str;
    }
}
punctuation signs in colnames are replaced by ..X

punctuation signs in colnames are replaced by ..X


By : Richard Watson
Date : March 29 2020, 07:55 AM
help you fix your problem I am having troubles with column names containing a punctuation sign. I diagnosed the issue as follows: , We need to use check.names=FALSE
code :
spamd <- read.table(file, sep = "" , header = F, stringsAsFactors= F,
                col.names = columnNames, check.names = FALSE)
Deleting stop-words and punctuation signs

Deleting stop-words and punctuation signs


By : Royston
Date : March 29 2020, 07:55 AM
this one helps. You have to iterate on tokenize(new['title']) and use De Morgan's laws to simplify the if statement:
code :
import string

stops = ['will', 'be', 'to', 'the', 'in']

tk = ['medium', ':', 'russian', 'athlete', 'will', 'be', 'admit', 'to', 'the',
      '2018', 'olympics', 'in', 'neutral', 'status']

# delete punctuation signs & stop-words
tk = []
for t in tokenize(new['title']):
    # if not ((t in string.punctuation) or (t in stops)):
    if (t not in string.punctuation) and (t not in stops): # De Morgan's laws
        tk.append(t)
print(tk)
['medium', 'russian', 'athlete', 'admit', '2018', 'olympics', 'neutral', 'status']
stops = ['will\n', 'be\n', 'to\n', 'the\n', 'in\n']
stops = [item.strip() for item in stops]
print(stops)
['will', 'be', 'to', 'the', 'in']
tk = [x for x in tokenize(new['title']) if x not in stops and x not in string.punctuation]
import string

stops = ['will', 'be', 'to', 'the', 'in']

tk = [
    'medium',  # 0
    ':',  # 1
    'russian',  # 2
    'athlete',  # 3
    'will',  # 4
    'be',  # 5
    'admit',  # 6
    'to',  # 7
    'the',  # 8
    '2018',  # 9
    'olympics',  # 10
    'in',  # 11
    'neutral',  # 12
    'status'  # 13
]

# delete punctuation signs & stop-words
for t in tk:
    print(len(tk), t, tk.index(t))
    if (t in string.punctuation) or (t in stops):
        tk.remove(t)

print(tk)
(14, 'medium', 0)
(14, ':', 1)
(13, 'athlete', 2)
(13, 'will', 3)
(12, 'admit', 4)
(12, 'to', 5)
(11, '2018', 6)
(11, 'olympics', 7)
(11, 'in', 8)
(10, 'status', 9)
['medium', 'russian', 'athlete', 'be', 'admit', 'the', '2018', 'olympics', 'neutral', 'status']
Java, split string by punctuation sign, process string, add punctuation signs back to string

Java, split string by punctuation sign, process string, add punctuation signs back to string


By : AlphaCrow
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I have string like this: , How about doing the whole thing in one tiny line?
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