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Program crashing with 'std::out_of_range' error


Program crashing with 'std::out_of_range' error

By : Vinicius Branco
Date : November 22 2020, 07:01 PM
fixed the issue. Will look into that further I am working on a wheel of fortune project for school and am running into some issues with pointers.
code :
std::string* arr_temp =  new std::string[100];
std::string* arr_temp1 = new std::string[100];
std::string* arr_temp;
std::string* arr_temp1;
std::string str1 = "THIS LINE IS THE GAME"; //makes a new string
*arr_temp1 = str1; //dereferences arr_temp1 and sets arr_temp1[0] to whatever str1 currently is


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C++ std::out_of_range error when I try to run the program

C++ std::out_of_range error when I try to run the program


By : toomuchcoffeman
Date : March 29 2020, 07:55 AM
To fix the issue you can do As other answers have already pointed out, in substr
If the position passed is past the end of the string, an out_of_range exception is thrown.
code :
for (int j = i; j<(i+4); j++)
Program crashing in Xcode with no error shown

Program crashing in Xcode with no error shown


By : Gercek Ad
Date : March 29 2020, 07:55 AM
this will help The naming convention copyNextSampleBuffer implies that you own the object returned so you are correct to release it, but you are calling the copyNextSampleBuffer method multiple times in a loop and overwriting the previous copy without releasing it.
When you do finally call CFRelease, you are calling it on a variable that you have just checked to be NULL. According to this StackOverflow answer, calling CFRelease on NULL is not safe, so that's why you're crashing:
code :
CMSampleBufferRef sample = [readerOutput copyNextSampleBuffer];

while( sample != NULL)
{
    CFRelease(sample);
    sample = [readerOutput copyNextSampleBuffer];
}
CMSampleBufferRef sample = [readerOutput copyNextSampleBuffer];

while( sample == NULL)
{
    sample = [readerOutput copyNextSampleBuffer];
}

CFRelease(sample);
SpriteKit crashing with std::out_of_range: vector issue

SpriteKit crashing with std::out_of_range: vector issue


By : adav
Date : March 29 2020, 07:55 AM
like below fixes the issue I've seen this error occur when you are trying to run an + (SKAction *)animateWithTextures:(NSArray *)textures action using an array that's nil or contains objects other than SKTexture. Set up logs on the texture arrays you're passing to your animate actions to see if all the items are being added correctly. Or maybe some texture arrays are being initialized/filled up after the animate action is run.
Program that shifts letters 3 letters forward, error: terminate called after throwing an instance of 'std::out_of_range'

Program that shifts letters 3 letters forward, error: terminate called after throwing an instance of 'std::out_of_range'


By : delpiano
Date : March 29 2020, 07:55 AM
I hope this helps . You’re trying to set characters in the string conversion, which has zero length. That’s why you get the error. All at() calls on that string are invalid.
You need to first copy the input string into conversion, and only then modify that. Or reserve enough space and push_back letters into it. Or simply use input all along.
code :
#include <iostream>
#include <string>

int main() {
  using namespace std;
  while (true) {
    string input;
    cout << "> " << flush;
    if (!getline(cin, input) || input.empty()) return 0;
    cin >> ws; // consume '\n'
    for (char &c : input) {
      char base = '\0';
      if (c >= 'a' && c<= 'z') base = 'a';
      else if (c >= 'A' && c <= 'Z') base = 'A';
      if (base) {
        c -= base;
        c = (c + 3) % ('z' - 'a');
        c += base;
      }
    }
    cout << "< " << input << endl;
  }
}
how to stop your program crashing from value error in python?

how to stop your program crashing from value error in python?


By : Lalkar
Date : March 29 2020, 07:55 AM
may help you . You can check the type of input to avoid getting the value error.
Check the code below:
code :
import random

print("choose a die: \n 1 = d4 \n 2 = d6 \n 3 = d8 \n 4 = d10 \n 5 = d12 \n 6 = d20 \n 7 = d100 \n or 0 to quit program")

#Initialization out of any of the expected values
u_input = 500

while u_input != 0:

    u_input = input()
    if type(u_input) != int:
        print("Entered input is not of int type")
        u_input = 500
        continue

    if u_input == 1:
       print("rolled a: [", random.randrange(1, 5), "] on a d4")

    elif u_input == 2:
        print("rolled a: [", random.randrange(1, 7), "] on a d6")

    elif u_input == 3:
        print("rolled a: [", random.randrange(1, 9), "] on a d8")

    elif u_input == 4:
        print("rolled a: [", random.randrange(1, 11), "] on a d10")

    elif u_input == 5:
        print("rolled a: [", random.randrange(1, 13), "] on a d12")

    elif u_input == 6:
        print("rolled a: [", random.randrange(1, 21), "] on a d20")

    elif u_input == 7:
        print("rolled a: [", random.randrange(1, 101), "] on a d100")
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