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Replacing all characters in a regular expression match with another character?


Replacing all characters in a regular expression match with another character?

By : dtest11
Date : November 22 2020, 07:01 PM
Hope that helps With sed you need to filter out lines that don't contain Hello there using an address:
code :
/Hello there/{...}
s/(^.*Hello there *)?[^[:space:]]/\1x/g
$ sed -r '/Hello there/{s/(^.*Hello there *)?[^[:space:]]/\1x/g}' file
Hello there xxxx xxxxx
Have fun
Hello there xxxxxxxx xxxxxxx


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regular expression to match string of characters only if it is not followed by a specific character

regular expression to match string of characters only if it is not followed by a specific character


By : Holmes911
Date : March 29 2020, 07:55 AM
Any of those help I need a regular expression which will match a string only if it doesn't followed by a forward slash (/) character and I want to match whole string. , This
code :
^/[^/]+/details/[^/]+$
/Raj/details/002-542545-1145457
/Raj/details/002-542545-1145457/show
How to add regular expression to match alphanumeric character with some special characters

How to add regular expression to match alphanumeric character with some special characters


By : Ben Messick
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I have the words with special character like , Try this regex
code :
[\w-]+
ABC12-xy
ABCD
ABC12_12
12-AB_xy
Regular Expression to Match character at a position and ignore characters after

Regular Expression to Match character at a position and ignore characters after


By : Wayne Cochran
Date : March 29 2020, 07:55 AM
I wish did fix the issue.
Though this matches the first 7 characters, it doesn't match the whole string.
code :
.{6}[A-Z-].*
Exclude the match for the special character # and all the characters after # within a regular expression

Exclude the match for the special character # and all the characters after # within a regular expression


By : user3391676
Date : March 29 2020, 07:55 AM
it should still fix some issue I'm trying to figure it out how to exclude the special character # + the last characters after the special character #. , Try this:
code :
^((?:http|https):\/\/(?:www\.)?website.com\/menu\/sub_menu\/sub_sub_menu\/)([^#]*)(.*)$
Regular Expression to match both first characters and last character in oracle

Regular Expression to match both first characters and last character in oracle


By : Momen Kamal
Date : March 29 2020, 07:55 AM
wish of those help I have a table with a column with the structure: Table name : re_result , You do not need regular expressions; a simpler LIKE may do the work:
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