Building all combinations of a vector - looking for a nicer way

Building all combinations of a vector - looking for a nicer way

By : noahcartersc
Date : November 21 2020, 07:01 PM
hop of those help? I have a simple case which I could solve in an ugly way, but I am sure a much cleverer (and faster) way must exist. , Loud debugging? I just found this way
code :

  V1 V2
1   1  2
2   1  3
3   1  4
4   1  5
5   1  6
6   2  3
7   2  4
8   2  5
9   2  6
10  3  4
11  3  5
12  3  6
13  4  5
14  4  6
15  5  6

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Building a Matrix of Combinations

Building a Matrix of Combinations

By : Trofim
Date : March 29 2020, 07:55 AM
wish help you to fix your issue OK, you want a sequence containing all 720 possible sequences. This is a bit trickier but it can be done.
The basic idea is the same as in my previous answer. In that answer we:
code :
Permutations<string> permutations = new Permutations<string>(foods);
IEnumerable<List<Pair>> query = 
    from permutation in permutations
    select colors.Zip(permutation, (color, food)=>new Pair(color, food)).ToList();
List<List<Pair>> results = query.ToList();
Determining all sub-vector combinations of a binary vector for a certain hamming weight

Determining all sub-vector combinations of a binary vector for a certain hamming weight

By : Walter Sanchez
Date : March 29 2020, 07:55 AM
To fix this issue The easiest way to approach this problem is to fetch all the non zero element indexes and thereby find a combinations of size y, of all these indexes.
For example:
code :
for i in index:
    binary_seq[i] = '0'
def foo(bin_seq, y):
    from itertools import combinations
    bin_seq = list(bin_seq)
    y = bin_seq.count('1') - y
    indexes = [i for i in range(len(bin_seq)) if bin_seq[i] == '1']
    for index in combinations(indexes,  y):
        vec = bin_seq[:]
        for i in index:
            vec[i] = '0'
        yield ''.join(vec)
>>> list(foo('0110110', 3))
['0010110', '0100110', '0110010', '0110100']
>>> list(foo('0110110', 2))
['0000110', '0010010', '0010100', '0100010', '0100100', '0110000']
Is there a nicer way of building an OracleCommand?

Is there a nicer way of building an OracleCommand?

By : user2728683
Date : March 29 2020, 07:55 AM
I hope this helps . I haven't tried this, but you should be able to do some linq fanciness with that loop and if condition:
code :
string selectStatement = "SELECT " + string.Join(", ", allC
    .Where(c => c.IsChecked.GetValueOrDefault())
    .Select(c => c.Content));
R: Building Conditional Combinations

R: Building Conditional Combinations

By : user3378194
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You can do this by using a merge, and reduce to loop over it.
At each level you will need to specify only the values you want to join on:
code :
level.1 <- data.frame(country = c("Netherlands", "New Zealand", "Europe"))
level.2 <- data.frame(country = c("Europe"), city = c('paris','london' ))
level.3 <- data.frame(country = c('Europe'), location = c('city', 'roads'))
level.4 <- data.frame(country = c('Europe'), regulation = c("A-Regulated", "G-Regulated", "C-Regulated"))
Reduce(function(x, y) merge(x, y, all=TRUE), list(level.1, level.2, level.3, level.4))

       country   city location  regulation
1       Europe  paris     city A-Regulated
2       Europe  paris     city G-Regulated
3       Europe  paris     city C-Regulated
4       Europe  paris    roads A-Regulated
5       Europe  paris    roads G-Regulated
6       Europe  paris    roads C-Regulated
7       Europe london     city A-Regulated
8       Europe london     city G-Regulated
9       Europe london     city C-Regulated
10      Europe london    roads A-Regulated
11      Europe london    roads G-Regulated
12      Europe london    roads C-Regulated
13 Netherlands   <NA>     <NA>        <NA>
14 New Zealand   <NA>     <NA>        <NA>
merge(merge(merge(level.1, level.2, all = TRUE), level.3, all = TRUE), level.4, all = TRUE)
deleting combinations of vector from a vector of vectors

deleting combinations of vector from a vector of vectors

By : user3388632
Date : March 29 2020, 07:55 AM
it helps some times I am not sure if I understood the question correctly. Suppose you have
code :
v = { { 1,0} , {0,1} , {1,2}}
v_final = { {1,0}, {1,2}}
 std::unordered_set<std::unordered_set<int>> x;
 x.insert( { 1,2} );
 x.insert( { 2,1} );
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