numpy.where - Weird behaviour: new elements spawning from nowhere?

numpy.where - Weird behaviour: new elements spawning from nowhere?

By : Lizzie Swanley
Date : November 21 2020, 07:01 PM
should help you out You are checking all elements in all columns, you need to use all along the first axis to find rows that are not all 0:
code :
(arr != 0).all(1)
>>> np.where((arr != 0).all(1))[0].shape

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numpy.nan weird behaviour in hashed object

numpy.nan weird behaviour in hashed object

By : Matthew Martel
Date : March 29 2020, 07:55 AM
will help you I am experiencing a weird behaviour when using numpy.nan that I can't understand. Here is a minimal example: , If you use
code :
_bool3key.__logic_sort__ = {0:-1, nan:0 , 1:1}
In [17]: _bool3key(float('nan'))
KeyError: nan
def _bool3key(x, logic_sort={0: -1, 1: 1}):
    Defines the keys used to order the list.
    The only allowed values are True, False, 1,0 and nan.
    return 0 if np.isnan(x) else logic_sort[x]
Weird behaviour with numpy array operations

Weird behaviour with numpy array operations

By : HCarlos
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , When you slice a numpy array as you are doing in the example, you get a view of the data rather than a copy.
numpy diff weird behaviour

numpy diff weird behaviour

By : Aravind
Date : March 29 2020, 07:55 AM
Hope that helps .tolist() is a better way of converting an array to a list (or nested lists). It carries the conversion all the way down. list() just iterates on one level. And since an array is already iterable, I don't think list(anarray) does anything useful.
start with an array:
code :
In [789]: z
Out[789]: array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9], dtype=uint8)
In [790]: type(list(z)[0])
Out[790]: numpy.uint8
In [791]: type([i for i in z][0])
Out[791]: numpy.uint8
In [792]: type(z.tolist()[0])
Out[792]: int
In [793]: np.diff(z.tolist())
Out[793]: array([1, 1, 1, 1, 1, 1, 1, 1, 1])
In [794]: np.diff(list(z))
Out[794]: array([1, 1, 1, 1, 1, 1, 1, 1, 1], dtype=uint8)
In [795]: np.diff(z.astype('int'))
Out[795]: array([1, 1, 1, 1, 1, 1, 1, 1, 1])
In [796]: np.diff(z)
Out[796]: array([1, 1, 1, 1, 1, 1, 1, 1, 1], dtype=uint8)
In [797]: np.array(list(z))
Out[797]: array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9], dtype=uint8)
Weird Python / numpy UnboundLocalError behaviour

Weird Python / numpy UnboundLocalError behaviour

By : Joel E. Datoon
Date : March 29 2020, 07:55 AM
will help you I am working on Python 2.7.12 and numpy 1.12.0 and observing the following behavior. Is this expected? I assumed that "a" to be in the scope w.r.t "f2" in both the cases how is accessing the "a" different than accessing a[ind, :]? , In your first example, you used augmented assignment:
code :
a += v
Numpy dotproduct weird behaviour

Numpy dotproduct weird behaviour

By : Freezyflame
Date : March 29 2020, 07:55 AM
Does that help From help(np.dot), we learn that, np.dot(x,y) is a sum product over the last axis of x and the second-to-last of y
In the case of np.dot(a, b), the last axis of a is 4 and the length of the only axis of b is 1. They don't match: fail.
code :
>>> np.dot(a, np.resize(b,a.shape[-1]))
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