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JSON SQlite3 Create table with JSON


JSON SQlite3 Create table with JSON

By : ajaykc
Date : November 20 2020, 07:00 PM
I hope this helps . While sqlite has functions for working with JSON data (Assuming the standard JSON1 extension is enabled in the instance of the library that you're using, of course), it does not have an actual JSON type. Instead, use TEXT columns to hold JSON text like you would any other string.
More reading on the data types that sqlite supports and how unknown types are treated in table defintions.
code :


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Paste JSON file in SQLITE3 table

Paste JSON file in SQLITE3 table


By : longbu
Date : March 29 2020, 07:55 AM
will be helpful for those in need Convert your json to XML and import to table(Using SQlite manager) if you want to import manually.
Otherwise, if you want to use php, You can explore about xml to db import options
Bind select dropdown for each table column (Head) from JSON, while binding JSON data to HTML table Jquery

Bind select dropdown for each table column (Head) from JSON, while binding JSON data to HTML table Jquery


By : Darjan
Date : March 29 2020, 07:55 AM
seems to work fine You can do it this way-
https://jsfiddle.net/9eemmbjc/1/
code :
var jsonResult=[
  {
    "Model": "Iphone 18",
    "Name": "iOS",
    "Share": 57.56,
    "Price Range": "$800 - $1000",
    "Brand": "Apple"
  },
  {
    "Model": "Nexus 23",
    "Name": "Android",
    "Share": 24.66,
    "Price Range": "$600 - $800",
    "Brand": "Samsung"
  },
  {
    "Model": "Tom-tom",
    "Name": "Java ME",
    "Share": 10.72,
    "Price Range": "$200 - $900",
    "Brand": "X Brand"
  }
]
var rowArray = new Array();

$.each(jsonResult,function(index,item){
  row=$("<tr/>");
    row.prepend('<td><select><option>Some option</select></td>');
         $.each(item,function(inx,el){
         $(row).append('<td>'+el+'</td>');
    });
    rowArray.push(row);
})

$('table').html(rowArray);
var selectRow= {
        Model:$('<select/>'),
        Name:$('<select/>'),
        Share:$('<select/>'),
        PriceRange:$('<select/>'),
        Brand:$('<select/>')
};

//select boxes at the top
$.each(jsonResult,function(index,item){
    selectRow.Model.append('<option>'+item.Model+'</option>');
    selectRow.Name.append('<option>'+item.Name+'</option>');
    selectRow.Share.append('<option>'+item.Share+'</option>');
    selectRow.PriceRange.append('<option>'+item["Price Range"]+'</option>');
    selectRow.Brand.append('<option>'+item.Brand+'</option>');
});

var dropdownRow= '<tr><th>'+selectRow.Model[0].outerHTML+'</th><th>'+selectRow.Name[0].outerHTML+'</th><th>'+selectRow.Share[0].outerHTML+'</th><th>'+selectRow.PriceRange[0].outerHTML+'</th><th>'+selectRow.Brand[0].outerHTML+'</th></tr>'
Android - JSON - How do I create a JSON Object & JSON Array to match this format using JSONObject & JSONArray Ty

Android - JSON - How do I create a JSON Object & JSON Array to match this format using JSONObject & JSONArray Ty


By : Mohamed Ahmed
Date : March 29 2020, 07:55 AM
Hope this helps You should be able to pass the JSON string directly to the constructor.
code :
JSONObject mainObject = new JSONObject(jsonString);
JSONObject mainObject = new JSONObject(); // Main Object.    
JSONArray categoryArray; // Category Array.    
JSONObject categoryObject; // Category Object.
JSONArray readingsMainArray; // An array of arrays.
JSONArray readingsChildArray; // A child array.
JSONObject readingsObject; // A readings entry.

// Create arrays.
readingsMainArray = new JSONArray();
readingsChildArray = new JSONArray();

// Create JSONObject.
readingsObject = new JSONObject();

// Put values.
readingsObject.put("Name":"SYS");
readingsObject.put("Type":"INT");
readingsObject.put("Value":"200");

// Add to the child array.
readingsChildArray.put(readingsObject);

// Repeat 3 times for the other values.

// Now add the readings child array to the main array.
readingsMainArray.put(readingsChildArray);

// Now the category JSONObject.
categoryObject = new JSONObject();

// Put values.
categoryObject.put("Category","BP);
categoryObject.put("CollectionTime","2015-12-28T09:09:22-05:00");
categoryObject.put("DeviceInfo",null);
categoryObject.put("Readings", readingsMainArray);

// Put the category object into the category array.
categoryArray = new JSONArray();
categoryArray.put(categoryObject);

// Repeat this process for the "second" category array.

// Add category array to the main object.
mainObject.put("PeripheralList",categoryArray);
How to create the config files ( tsconfig.json, typings.json, package.json)?

How to create the config files ( tsconfig.json, typings.json, package.json)?


By : Johan Wendin
Date : March 29 2020, 07:55 AM
this will help package.json
includes information about packages and libraries which are used by your project, also can include npm scripts which helps of running tasks of application like running tests, building js and so on...
Populating SQLite table with JSON data, getting: sqlite3.OperationalError: near "x": syntax error

Populating SQLite table with JSON data, getting: sqlite3.OperationalError: near "x": syntax error


By : iLearner
Date : March 29 2020, 07:55 AM
will be helpful for those in need Your current problem is the missing quotes around the string values in the query.
You need to properly parameterize your query letting the database driver worry about the type conversions, putting quotes properly and escaping the parameters:
code :
query = """
    INSERT OR IGNORE INTO 
        {} 
    VALUES 
        (?, ?, ?)""".format(table)

c.execute(query, (detail['id'], detail['name'], detail['description']))
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