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If else fill variable if empty list


If else fill variable if empty list

By : GetuOne
Date : November 20 2020, 07:00 PM
this one helps. I have lists that are empty and filled in the data. I am trying to the store last element of the list into a variable. If there are elements in the list, it is working fine. However, when I pass in a empty [] list, I get error like: IndexError: list index out of range. Which syntax I should be using for []? , Here is one way to do this:
code :
final = ids[-1] if ids else None


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Js doesn't fill the input with .val - when i post the form, the variable is empty

Js doesn't fill the input with .val - when i post the form, the variable is empty


By : user2471556
Date : March 29 2020, 07:55 AM
This might help you If you disable an input the value is not sent up to the server. That would be why there is no value being sent to the server. Either use a hidden input field or do not disable the input.
How do you fill a variable with an empty space in Python?

How do you fill a variable with an empty space in Python?


By : Hardik Chimedia
Date : March 29 2020, 07:55 AM
around this issue I am extracting the metadata of audio files to create full Titles. When I extract the metadata of a file, sometimes there are fields that are not filled up, thus returning a variable that is None. , After reading the value, use this:
code :
if title is None:
    title= ''
List comprehension- fill arbitrary value if list is empty

List comprehension- fill arbitrary value if list is empty


By : captainAmerica
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I am using a list comprehension to assign values to an object. In short, I have two lists. One which contains a collection of values and another which contains a collection of indices (from that previous list) , Like this?
code :
values = [1.4,1.5,1.6,1.8]
indices = [0,1]
a.newvalues = [values[i] for i in indices] if indices else [-1]
How do I fill an empty list in a for loop?

How do I fill an empty list in a for loop?


By : Muhammad Adnan Sami
Date : March 29 2020, 07:55 AM
I hope this helps . From what I understand, you want to select a range of components.
As always when trying to write generic code, put them inside a data structure. I suggest a list:
code :
choices = [nc3, ic4, nc4, ic5, nc5, nc6, nc7, nc9]
n = input("How many components are you gonna use? ")
components = choices[0:n]
chosen = input("Which components are you gonna use? ")
idxs = [int(x) for x in chosen.split(' ')]
components = [x for i, x in enumerate(choices) if i in idxs]
choices = [
    'nc3': nc3, 'ic4': ic4, 'nc4': nc4,
    'ic5': ic5, 'nc5': nc5, 'nc6': nc6,
    'nc7': nc7, 'nc9': nc9]

chosen = input("Which components are you gonna use? ")
names = [x for x in chosen.split(' ')]
components = [choices[x] for x in names]
Fill a list in a do loop returns the list empty

Fill a list in a do loop returns the list empty


By : Magvay
Date : March 29 2020, 07:55 AM
wish helps you I'm learning Racket and I don't know why lst is always empty: , This is how I make it work:
code :
(do ([x 6000 (- x 1)])
  ((zero? x))
  (set! lst (cons (my-procedure '((a . 1)(b . 2)(c . 3))) lst)))
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