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How can I store values in a hashmap with <String, List<Integer>>


How can I store values in a hashmap with <String, List<Integer>>

By : Sevilay Musddak
Date : November 20 2020, 07:00 PM
With these it helps I have the following array , Using java-8 you could use the following all in a single line :
code :
Map<String, List<Integer>> collect1 = 
     Arrays.stream(students).collect(Collectors.groupingBy(arr -> arr[0], 
              Collectors.mapping(arr -> Integer.parseInt(arr[1]), Collectors.toList())));


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HashMap<String, boolean> copy all the keys into HashMap<String, Integer>and initialize values to zero

HashMap<String, boolean> copy all the keys into HashMap<String, Integer>and initialize values to zero


By : Elemer Vadaszi
Date : March 29 2020, 07:55 AM
To fix this issue What is the best way ? , Don't think there's much need for anything fancy here:
code :
Map<String, Boolean> map = ...;
Map<String, Integer> newMap = Maps.newHashMapWithExpectedSize(map.size());
for (String key : map.keySet()) {
  newMap.put(key, 0);
}
Map<String, Integer> newMap = Maps.newHashMap(
    Maps.transformValues(map, Functions.constant(0)));

// 1-liner with static imports!
Map<String, Integer> newMap = newHashMap(transformValues(map, constant(0)));
How do I get the list of possible values in a HashMap<String, Integer>?

How do I get the list of possible values in a HashMap<String, Integer>?


By : Adrian Scholl
Date : March 29 2020, 07:55 AM
it helps some times I figured it out - here's the full logic for people who were wondering:
code :
public String[] sort(String[] data) {
    TreeMap<String, Integer> sortmap = new TreeMap<String, Integer>();
    ArrayList<String> stringlist = new ArrayList<String>();
    for(String x : data){
        if(sortmap.containsKey(x))
            sortmap.put(x, sortmap.get(x)+1);
        else
            sortmap.put(x, 1);
    }
    Arrays.sort(sortmap.values().toArray(), 0, sortmap.size());
    for (int i = data.length; i > 0; i--){
        for (Entry<String, Integer> k : sortmap.entrySet()){
            if (k.getValue() == i)
                stringlist.add(k.getKey());
        }
    }
    String[] output = stringlist.toArray(new String[stringlist.size()]);
    return output;
}
How can I store a HashMap <Integer, String> in android using shared preferences?

How can I store a HashMap <Integer, String> in android using shared preferences?


By : Ivan Dimitrov
Date : March 29 2020, 07:55 AM
Any of those help Hey I found a way in the end :)
I just changed the HashMap I had to format and then did the following to save the contents:
code :
SharedPreferences.Editor editor = getSharedPreferences(PREFS_NAME, 0).edit();
for( Entry entry : backUpCurency_values.entrySet() ) 
editor.putString( entry.getKey(), entry.getValue() );
editor.commit();
SharedPreferences prefs = getSharedPreferences(PREFS_NAME, 0);
for( Entry entry : prefs.getAll().entrySet() )
   backUpCurency_values.put( entry.getKey(), entry.getValue().toString() );
Convert a HashMap<Integer, List<String>> to HashMap<String, HashSet<Integer>>

Convert a HashMap<Integer, List<String>> to HashMap<String, HashSet<Integer>>


By : John
Date : March 29 2020, 07:55 AM
wish helps you Just looking at Duplicate link.
This is the final solution I have
code :
 private HashMap<String, HashSet<Integer>> process(HashMap<Integer, List<String>> input) {
     return input.entrySet().stream()
             .flatMap(entry -> entry.getValue().stream().map(s -> new SimpleEntry<>(entry.getKey(), s)))
             .collect(Collectors.groupingBy(SimpleEntry::getValue, HashMap::new,
                 Collectors.mapping(SimpleEntry::getKey, Collectors.toCollection(HashSet::new))));
     }
Is Java method with a single argument to receive values of both HashMap<String, Integer> and HashMap<Long, Inte

Is Java method with a single argument to receive values of both HashMap<String, Integer> and HashMap<Long, Inte


By : Ecc
Date : March 29 2020, 07:55 AM
I hope this helps you . You can introduce a T which needs to implement Comparable and then replace any usage of Long with T:
code :
static <T extends Comparable<T>> LinkedHashMap<T, Integer> sortNumberHashMapByKey(HashMap<T, Integer> map){
    ArrayList<T> keys = new ArrayList<>(map.keySet());
    ArrayList<Integer> values = new ArrayList<>(map.values());
    Collections.sort(keys);
    Collections.sort(values);
    LinkedHashMap<T, Integer> sortedMap = new LinkedHashMap<>();

    for (Integer value : values) {
        Iterator<T> keyIt = keys.iterator();
        while (keyIt.hasNext()){
            T key = keyIt.next();
            if (map.get(key).equals(value)){
                keyIt.remove();
                sortedMap.put(key, value);
                break;
            }
        }
    }
    return sortedMap;
}
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