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@synthesize comma separated list


@synthesize comma separated list

By : Sergio
Date : January 10 2021, 01:57 PM
wish helps you I've read apple's Objective-C doc and am curious about using @synthesize. I've seen classes with a long list of @synthesizes and I've seen classes with one @synthesize then a long comma-separated list of ivars. So what's the difference between: , It's purely a style choice, just like there's no difference between
code :


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Vim: Most efficient way to copy newline separated list in the middle of text to a comma separated list

Vim: Most efficient way to copy newline separated list in the middle of text to a comma separated list


By : Goot
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have this text: ,
Visually select your block.
code :
:'<,'>s/\n\*/,
xx
Compare items in comma separated list to another set of items in a comma separated list using limited Oracle SQL

Compare items in comma separated list to another set of items in a comma separated list using limited Oracle SQL


By : Mark Maggio Giocondo
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further While I absolutely agree with commentators that the data model is flawed, sometimes you have to work with what you're given. If it is really impossible to change the data model then you can do this, but it isn't entirely pretty, and depends on your 'restrictions' not excluding the use of common table expressions - I've seen tools struggle with those...
code :
with items_cte as (
  select id, regexp_substr(items, '[^,]+', 1, level) as item, level as pos
  from items
  connect by level <= regexp_count(items, '[^,]+')
  and prior id = id
  and prior sys_guid() is not null
),
list_cte as (
  select regexp_substr(:list, '[^,]+', 1, level) as item,
    count(*) over () as list_length
  from dual
  connect by level <= regexp_count(:list, '[^,]+')
)
select i.id, listagg(i.item, ',') within group (order by i.pos) as items
from items_cte i
join list_cte l
on l.item = i.item
group by i.id
having count(distinct i.item) = max(l.list_length)
order by i.id;

        ID ITEMS
---------- --------------------------------------------
         1 ItemA,ItemB,ItemC
         2 ItemC,ItemB,ItemA
         3 ItemC,ItemA,ItemB,ItemB
Find comma separated value in a column by using comma separated list

Find comma separated value in a column by using comma separated list


By : Peter Bienek
Date : March 29 2020, 07:55 AM
wish of those help I have a a column item_id_list with comma separated id such as this: , You could use a OR with find_in_set
code :
    SELECT * FROM task_detail 
    WHERE FIND_IN_SET('21', item_id_list)
    OR  FIND_IN_SET('79', item_id_list)
Excel formula to check if items from a comma separated list in one cell exist in a comma separated list in another cell?

Excel formula to check if items from a comma separated list in one cell exist in a comma separated list in another cell?


By : Klaire Attard
Date : March 29 2020, 07:55 AM
Hope that helps I have a spreadsheet where every row has two columns, each containing a comma separated list of words or phrases. , Use this array formula:
code :
=AND(ISNUMBER(SEARCH(", " & TRIM(MID(SUBSTITUTE(B1,",",REPT(" ",99)),(ROW($XFD$1:INDEX(XFD:XFD,LEN(B1)-LEN(SUBSTITUTE(B1,",",""))+1))-1)*99+1,99)) & ",",", "&A1&",")))
Filter rows by matching comma separated list against comma separated list

Filter rows by matching comma separated list against comma separated list


By : user5986990
Date : March 29 2020, 07:55 AM
Hope that helps I have the below table , You could simply use the LIKE operator, as follows :
code :
SELECT *
FROM mytable
WHERE Col2 LIKE '%ABS%' OR Col2 LIKE '%MCM%'
SELECT *
FROM mytable t
WHERE EXISTS (
    SELECT 1
    FROM (SELECT val FROM STRING_SPLIT('ABS, MCM', ',')) x
    WHERE CONCAT(',', t.Col1, ',')
        LIKE CONCAT('%,', x.val, ',%')
)
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