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Starting from which integer is it better to switch to another product brand versioning scheme (year-based, codenames, ..


Starting from which integer is it better to switch to another product brand versioning scheme (year-based, codenames, ..

By : wfdctrl
Date : January 10 2021, 01:49 PM
will be helpful for those in need As ever, the answer is 42.
EDIT: Oh, alright, I admit that sometimes the answer to questions on SO is 'Emacs'.
code :


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Value-based color scheme for year-by-year histograms in R

Value-based color scheme for year-by-year histograms in R


By : DevinK
Date : March 29 2020, 07:55 AM
Does that help Using ggplot, to control the color, the easiest way is to get a variable into the data frame which indicates which group it is a part of (the within or outside reference range group). This can be accomplished by a series of steps. First, for each case, match up the appropriate limits based on the year.
code :
Gboth <- merge(Gval2, Gref2, by.x="Year", by.y="REFERENCE_YEAR")
Gboth$within <- factor(Gboth$REFERENCE_LOW < Gboth$Value & 
                       Gboth$Value <= Gboth$REFERENCE_HIGH,
                       levels = c(FALSE, TRUE),
                       labels = c("Outside reference range",
                                  "Within reference range"))
ggplot(Gboth, aes(x=Value)) +
  geom_histogram(aes(fill=within), binwidth=10) +
  facet_wrap( ~ Year) +
  scale_x_continuous("Glucose Levels in mg/dl") +
  scale_y_continuous("Frequency") +
  scale_fill_manual("", breaks=c("Outside reference range", 
                                 "Within reference range"),
                    values = c("black", "red")) +
  opts(title = "Distribution of Glucose Levels")
How to calculate current school year based on two-digit starting year?

How to calculate current school year based on two-digit starting year?


By : Kapil Agarwal
Date : March 29 2020, 07:55 AM
This might help you I'd say you're off to a good start. All you need to do is fix the wrap-around issue by adding 100 to the difference if it's negative:
code :
$yr = substr($_SESSION["username"], 1, 2);    
$cur = date("y");  // two-digit year
$diff = $cur - $yr;
if ($diff < 0) $diff += 100;
[MySQL]: Get product row - if doesn't exist by brand & product_code - get only by brand where product_code is empty

[MySQL]: Get product row - if doesn't exist by brand & product_code - get only by brand where product_code is empty


By : Xin Xiong
Date : March 29 2020, 07:55 AM
help you fix your problem I have a table of shop_product_videos: , simple use OR
code :
SELECT link FROM shop_product_videos 
WHERE brand='$brand' 
AND (product_code is null or product_code='$product_code') 
LIMIT 1
SELECT link FROM shop_product_videos 
WHERE brand='$brand' 
AND ( product_code='$product_code' or product_code='' or product_code is null) LIMIT 1
laravel 5.6: How to display each product and the available brand s in a table given that each product has multiple brand

laravel 5.6: How to display each product and the available brand s in a table given that each product has multiple brand


By : Fon
Date : March 29 2020, 07:55 AM
this one helps. Have you tried using a collection method to constrain what brands are used in the foreach? IE:
code :
@foreach($brands->where('pid', $detail->product_id) as $brand )
    <span>{{$brand->name}}</span>
@endforeach
How to get the product of one and every third integer that is less than a given limit starting with 3 - EXCEPT those div

How to get the product of one and every third integer that is less than a given limit starting with 3 - EXCEPT those div


By : verycrazy
Date : March 29 2020, 07:55 AM
this one helps. If the limit be 21. The output should be 18*12*9*6*3*1. This is what I got so far. , Here’s a method that I believe does what you want.
code :
public double findProduct(int limit) { 
    double product = 1;
        for(int n = 3; n < limit; n = n + 3) {
            if (n%5 != 0)
        {
                product = product * n;
            }
       }
    return product;
}
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