Text box entered date should be in dd/MM/yyyy while creating date object using Jscript
By : user6584839
Date : March 29 2020, 07:55 AM
I hope this helps you . enter code hereSuggest me on this.. While creating Date ref(java script), text box value should be treated as dd/MM/yyyy format.. , Try this: code :
var dateString = document.getElementById('<textboxid>').value;
var day = parseInt(dateString.substring(0,2));
var month = parseInt(dateString.substring(3,5));
var year = parseInt(dateString.substring(6,10));
alert(new Date(year, month - 1, day));
alert(/^(0[1-9]|[12][0-9]|3[01]|[1-9])[- /.](0[1-9]|1[012]|[1-9])[- /.](\d{4})$/.test(dateString));
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java.text.ParseException: Unparseable date: convert mm/dd/yyyy string to a date
By : user2430072
Date : March 29 2020, 07:55 AM
around this issue There are several potential problems here: You're not specifying a format You're not specifying a locale You're not specifying a time zone You're trying to cast the return value (which will be a java.util.Date reference) to a java.sql.Date - that would fail code :
DateFormat df = new SimpleDateFormat("MM/dd/yyyy", Locale.US);
df.setTimeZone(...); // Whatever time zone you want to use
Date journeyDate = new java.sql.Date(df.parse(text).getTime());
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how to convert date in text field to UK date format of dd/mm/yyyy in ms access?
By : 007admin
Date : March 29 2020, 07:55 AM
this one helps. You must convert your text date to true for any comparison to work. So (in Access): code :
Select columns From table Where DateSerial(Mid(jobdate, 7, 4), Mid(jobdate, 4, 2), Mid(jobdate, 1, 2) >= Date()
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Convert text formatted date DD.MM.YYY HH.MM to standart DD.MM.YYYY date format in Excel
By : Gabriel Morin
Date : March 29 2020, 07:55 AM
Hope that helps I have a very troublesome date format that I need to convert to standart short date as DD.MM.YYYY. I have tried some formulas as below but I cannot reach the true output. Any help will be appreciated... , Use this: code :
=DATE(MID(A1,7,4),MID(A1,4,2),LEFT(A1,2))
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Find date/financial quarter in file name (yyyy/mm/dd) then change date in file name to yyyy/mm/dd + 3 months
By : Ashish Gautam
Date : March 29 2020, 07:55 AM
should help you out Step one is to write a generator that yields date strings in three month increments from a given date string to the present. We can store the initial date in a datetime object, using that to generate the new date strings at every step, and keep the dates from moving past the present. Then we can use calendar.monthrange to find the last days of the given months. code :
from datetime import datetime
from calendar import monthrange
def dates_from(start):
date = datetime.strptime(start, "%Y%m%d")
today = datetime.today()
while date < today:
yield date.strftime("%Y%m%d")
month = date.month + 3
year = date.year
if month > 12:
year += 1
month -= 12
_, day = monthrange(year, month)
date = datetime(year, month, day)
sql_template = """\
SELECT
(SELECT
PCR.repdte
FROM
All_Reports_{0}_Performance_and_Condition_Ratios as
PCR) AS Quarter,
(SELECT
Round(AVG(PCR.lnlsdepr))
FROM
All_Reports_{0}_Performance_and_Condition_Ratios as
PCR) AS NetLoansAndLeasesToDeposits,
(SELECT sum(CAST(LD.IDdepsam as int))
FROM
'All_Reports_{0}_Deposits_Based_on_the_Dollars250,000
_Reporting_Threshold' AS LD) AS
DepositAccountsWith$LessThan$250k"""
queries = map(sql_template.format, dates_from("19921231"))
output_string = "\nUNION ALL\n".join(queries)
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