Multiple kernels in cuda 4.0
By : hugmin42
Date : March 29 2020, 07:55 AM
should help you out To use multiple GPUs from a single thread, you can switch between cuda contexts (each of which is bound is bound to a GPU) and launch kernels asynchronously. In effect you will be running multiple kernels across multiple GPUs this way. However if you have cards with compute capability > 2.0, you can also run kernels concurrently as shown in the comments above. You can find the post about concurrent kernel execution over here.
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launching multiple kernels cuda
By : Feray
Date : March 29 2020, 07:55 AM
may help you . You are defining the same variables twice. You could e.g. eliminate that error simply by limiting the scope of each definition through additional blocks ({...} pairs): code :
int k,sim_step;
int counter_top,counter_bottom;
............
...................
for(k=0;k<=sim_step;k++)
{
{
dim3 gridDim(1,1);
dim3 blockDim(counter_top,1,1);
agent_movement_top<<<gridDim,blockDim>>>(args..) ;
}
{
dim3 gridDim(1,1);
dim3 blockDim(counter_bottom,1,1);
agent_movement_bot<<<gridDim,blockDim>>>(args...);
}
}
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Can i just define CUDA kernels in .h files?
By : Lynn Hoffman
Date : March 29 2020, 07:55 AM
it helps some times The rules and behavior here aren't really any different conceptually than what is permissible in C or C++ coding. For a file that is explicitly included in another file via an #include directive, the file name, and indeed the file extension - .cu, .h, .cuh. .hpp or what have you, really doesn't matter. That is just a directive to the compiler to pick up that file, and insert it at this point in the source, just as if it had been typed there.
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CUDA FFT plan reuse across multiple 'overlapped' CUDA Stream launches
By : Dorian Gray
Date : March 29 2020, 07:55 AM
seems to work fine What I'm doing is to create and lauch a new CUDA stream as a result of a complete pulse transmission.
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Where to define CUDA kernels in a program with multiple source files
By : chandra putra
Date : March 29 2020, 07:55 AM
I hope this helps . The program you describe is still very simple (which is why I'm able to venture an answer... that also ignores your code). What I think you need to do is the following:
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