radio value lost by $_post array

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By : Christian Peter

Date : January 02 2021, 06:48 AM

Does that help PHP's standard form parsing system (which populates $_POST) can't handle multiple bits of form data with the same name (unless that name ends with the characters []).
Change the name of the submit button.

code :

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PHP $_POST value being lost when using JS .insertAfter()

By : Dante Fung

Date : March 29 2020, 07:55 AM

This might help you If you have a select with name = enquiry_source and then you ad an input with the same name only one element is posted to the server, in your case the input field (only the latter element is posted) so you should give the field a different name

code :

        var field_to_append = '<div id="form-field-enquiry_source_other" class="form-field float-left">'+
            '<label>Other<span class="required"></span></label>'+
            '<input name="enquiry_source_other" id="form-field-input-enquiry_source_other" />'+
            '</div>';

Previously set array variable using $_POST method is lost after checking button clicked using $_POST

By : Atelu peter orinyo

Date : March 29 2020, 07:55 AM

To fix this issue an Idea, you need to store it in session. it seems you get $_POST['user'] from previous page/request. variable $_POST only used for passing variable between page, It will not exist anymore if you reload the page.
do it like:

code :

$user = $_SESSION['user'] = array_filter(array_map('array_filter', $_POST['user']));

Session variable lost after $_Post in php

By : Nhã

Date : March 29 2020, 07:55 AM

seems to work fine The value of $_POST['inputCount'] is being assigned to your session variable regardless of how the page is loaded.
In other words, when you post back using the checkout button, rather than pulling the value of inputCount from the session, you're overwriting the value based on the current $_POST['inputCount'], and then reading that from the session (which is redundant).

code :

require("includes/db.php");
require("includes/functions.php");

session_start();  

//check if the form has been submitted
if(!isset($_POST['checkoutButton'])){
    $inputCount = mysql_real_escape_string($_POST['inputCount']);
    $_SESSION['InputCount'] = $inputCount;   //it is ok at the begining
} else {
    $iteration = $_SESSION['InputCount'];
    var_dump ($iteration);

    $userID = $_SESSION['UserID'];
}

How can I group radio together and still pass them through $_POST as an array?

By : user3385392

Date : March 29 2020, 07:55 AM

should help you out So the approach I ended up using was to look through $_POST for arrays and then merge them. (Obviously, this only works if you know that the only arrays in $_POST are of the type you need…). This is, roughly, my PHP:

code :

    $firstElem = true;
    foreach ($_POST as $element){           
        if( is_array($element) ){
            if($firstElem){
                $firstElem = false;
                $members = $element;
            }else{
                $members = array_merge($members, $element);
            }
        }
    }