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Linq2Sql How to write outer join query?


Linq2Sql How to write outer join query?

By : Ketan Attarde
Date : January 02 2021, 06:48 AM
I think the issue was by ths following , I have following SQL tables. , It would be just as simple as
code :


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Not able to write left outer join for same table query in MS Access database

Not able to write left outer join for same table query in MS Access database


By : Dejan Cosic
Date : March 29 2020, 07:55 AM
will help you Try this one (TOP (100) PERCENT and I think also LEFT JOIN is unnecessary) -
code :
SELECT
      t.pname
    , t.SlNo AS PNum
    , t.pname AS CName
    , t.Prnt
FROM Tree AS t
--LEFT OUTER JOIN Tree AS t2 ON t.Prnt = t2.SlNo
WHERE t.Ref = 155
ORDER BY t.Prnt
how to write combination of RIGHT OUTER JOIN and LEFT OUTER JOIN

how to write combination of RIGHT OUTER JOIN and LEFT OUTER JOIN


By : Lon Sokanya
Date : March 29 2020, 07:55 AM
I hope this helps you . Could any one help me to resolve the below query.. , Try this:
code :
SELECT X.master_key, X.vendor_code  
FROM X 
INNER JOIN Y ON X.parent_key = Y.master_key 
LEFT OUTER JOIN X AS x2 ON x2.parent_key = Y.master_key AND x2.INITIALS = Y.DEFAULT_INITIALS AND x2.VENDOR_CODE = Y.VENDOR_ABBREV 
WHERE Y.project_name = 'TEST' 
SELECT vnd.master_key, vnd.vendor_code  
FROM vnd
INNER JOIN vnm ON vnm.master_key = vnd.parent_key AND vnm.inactive = 0 
LEFT OUTER JOIN vnd vn2 ON vnm.master_key = vn2.parent_key AND vn2.INITIALS = vnm.DEFAULT_INITIALS AND vn2.VENDOR_CODE = vnm.VENDOR_ABBREV
WHERE vnd.inactive = 0 AND vnm.project_name = 'TEST'  
ORDER BY LOWER(vnm.company_name   +  ' '), LOWER(vnd.vendor_code)  ,LOWER(vnd.first_name   +  ' '), LOWER(vnd.last_name   +  ' ')
How to Write Left Outer join for this SQL query?

How to Write Left Outer join for this SQL query?


By : Sufia Soni
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I had a table like , I have modified the query according to your required output
code :
    DECLARE @Table1 TABLE 
        (Id INT, Message VARCHAR(7), Call INT, status VARCHAR(7), EMail VARCHAR(11), subject VARCHAR(12))
    ;

    INSERT INTO @Table1
        (Id, Message, Call, status, EMail, subject)
    VALUES
        (1, 'hi', 2222, 'Replied', 'g.m.p@m.com', 'Log a cll'),
        (2, 'hello', 2222, 'Replied', 'g.m.p@m.com', 'Re:'),
        (3, 'hi2', 2222, 'New', 'g.m.p@m.com', 'Re:log a cll'),
        (4, 'hello2', 2223, 'Read', 'g.p@m.com', 'Log a cldf'),
        (5, 'how r u', 2223, 'New', 'g.p@m.com', 'Re:Log a')
    ;

        SELECT T.Id,
        TT.Message,
        TT.Call,
        TT.status,
        TT.EMail,
        TT.subject 
        FROM @Table1 tt 
        LEFT OUTER JOIN 
        (
        SELECT Id,
        MAX(subject) OVER(PARTITION BY call ORDER BY call) subject,
        MAX(Message) OVER(PARTITION BY call ORDER BY call) Message  FROM @Table1)T
        ON T.Id = TT.Id AND T.Message = TT.Message AND T.subject = TT.subject
WHERE T.id IS NOT NULL 
find the number of records that left outer join,right outer join and full outer join return

find the number of records that left outer join,right outer join and full outer join return


By : blueblood
Date : March 29 2020, 07:55 AM
like below fixes the issue Since you know the total number of records, knowing the number of unmatched records is equivalent to knowing the number of matched records. (Perhaps!)
The answer to your question is NO, you can't determine the number of records in different types of joins by only knowing the cardinalities of the base tables, without knowing how many records are matched (or unmatched). Simple mental exercise: both tables have 100 records. If all are perfectly matched, one-to-one, then all joins are the same as the inner join, and they all have 100 records. If there are no matches at all, the inner join has zero rows, the one-sided joins have 100 rows and the full outer join has 200 rows. And the only difference between these cases is the number of matched (or unmatched) records, there is absolutely nothing else that you might know that will allow you to get the answer without this piece of information.
How do I write a full outer join query in access

How do I write a full outer join query in access


By : Mailen Havela
Date : March 29 2020, 07:55 AM
it should still fix some issue Assuming there are not duplicate rows in AA and BB (i.e. all the same values), a full outer join is the equivalent of the union of a left join and a right join.
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