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Populating a Dropdown list in PHP dynamically


Populating a Dropdown list in PHP dynamically

By : user3863764
Date : January 02 2021, 06:48 AM
hop of those help? Option 1: embed the data for the second select in the document as hidden elements or JS objects. A change event handler on the first select will populate the second select. A List Apart has an example dynamic select page.
Option 2: use AJAX. When the first select changes, make a request to the server for the contents of the second select, then populate it. With a JS library (such as jQuery), this becomes quite easy.
code :


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Dynamically populating a dropdown with jQuery

Dynamically populating a dropdown with jQuery


By : Cristhian Camilo Lop
Date : March 29 2020, 07:55 AM
I wish this helpful for you How do I remove all the values from a dropdown list using jQuery?
code :
$('#items').html('');
Proper populating of dropdown list in asp.net dynamically

Proper populating of dropdown list in asp.net dynamically


By : siva shankari
Date : March 29 2020, 07:55 AM
Hope that helps From my point of view the easiest and the best solution is to set the DropDownList's DataSource property. In this case, all the required job is done behind the scene and you neednd't think of a synchronization data between the db server and web server.
Also, if I were you, I would modify the sql so that only a single request to be sent to the DB server, i.e.
code :
"select Classification from schemaItemDetails.AssetClassification where AC_ID between 1 and 20"
Dynamically populating a dropdownlist based on selected value in another dropdown list

Dynamically populating a dropdownlist based on selected value in another dropdown list


By : zrthas.zheng
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have two dropdown lists, where one is populated on page load and the other should only be populated when a value is selected in the first one. The first dropdown list is defined as: , 1st set AutoPostBack="True" property of base_ddl
and then
code :
secondary_ddl.Items.Clear();
IList<InfoContainer> info = getInfoBasedOnSelected(base_ddl.Value);
secondary_ddl.DataTextField = "name";
secondary_ddl.DataValueField = "value";
secondary_ddl.DataSource = info;
secondary_ddl.DataBind();
Angularjs 1.5 & angular material: Populating a dropdown list based on another dropdown list

Angularjs 1.5 & angular material: Populating a dropdown list based on another dropdown list


By : mamktpma
Date : March 29 2020, 07:55 AM
this one helps. I have my country list and state list in my angular controller. My problem is that I want to hide the state dropdown list if the country does not contain the states. I tried using ng-show but it didn't work. I am using angular 1.5. Any idea? , Try this:
code :
$scope.getCountryStates = function (countryId) {
    $scope.states = ($filter('filter')($scope.statelist, { countryId: countryId }));

    var stateList = $scope.statelist;
    for(var i = 0; i < stateList.length; i++)
    {
        countryId != stateList[i].countryId ? $scope.showStates = false : $scope.showStates = true;
    }
};
Populating dropdown dynamically from list with Jinja

Populating dropdown dynamically from list with Jinja


By : user3575024
Date : March 29 2020, 07:55 AM
should help you out I have a Flask application which, from one of its routes, produces a list of data that I would then like to display in a dropdown menu on the front-end. The issue is, a different number of items will exist in each list that will populate the same dropdown menu. For example, one users accounts might have three items, while another's might have twenty. , you can use the following syntax to loop your list
code :
<select>
    {% for x in list %}
    <option value="{{x.id}}">{{x.text}}</option>
    {% endfor %}
</select>
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