Recognizing when to use the modulus operator

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By : rafey

Date : January 02 2021, 06:48 AM

I hope this helps . Imagine that you have an elapsed time in seconds and you want to convert this to hours, minutes, and seconds:

code :

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C# modulus operator

By : Niko Bellic

Date : March 29 2020, 07:55 AM

hop of those help? Because the remainder of 3 / 4 = 3.
http://en.wikipedia.org/wiki/Modulo_operator

FInd modulus without using modulus operator

By : Ameer Hamza Awan

Date : March 29 2020, 07:55 AM

will help you I assume you're trying to calculate the modulus of a number without the modulus operator. Well, this is how it can be done manually:

code :

while ($b <= $a) {
    $c = $a - $b;
    $a -= $b;
}
echo $c; // => 2

Javascript: Why does prefix operator work with modulus but not postfix operator?

By : user3454578

Date : March 29 2020, 07:55 AM

it fixes the issue I am trying to make a function that increments until it reaches 3 and then starts back from zero (so, called three times it would log 0 then 1 then 2. When using the % operator with the pre and post fix operators, I have confusing results. , This doesn't have anything to do with the modulo operator. Even

code :

i = i++;

i = (i + 1) % 3;

% Modulus Operator in DB2 V.9

By : user1522737

Date : March 29 2020, 07:55 AM

This might help you You wouldn't use the % operator, SQL is not a full programming language. You will want to use the MOD(); function and this is how:

code :

MOD( dividend, divider )

SELECT T.VendorID, T.Amount, T.Date, ROW_NUMBER () OVER (PARTITION BY T.VendorID, T.Amount ORDER BY T.Date) as "Order"
FROM TABLE T
WHERE T.Amount >= 1000 AND MOD(T.Amount,5) = 0;

C++ Modulus operator Vs. Shift operator, which is faster and why?

By : Raj Thakur

Date : March 29 2020, 07:55 AM

will be helpful for those in need I was working on the code to find prime number, and during my work i became curious how exactly % operation in C++ works in low level. ,
I really want to know how '%' works in lower level!

code :

int main()
{
    int x = 100;

    int mod = x % 128;
    int shift = x >> 7;

    return 0;
}

main:
    push    rbp
    mov     rbp, rsp
    xor     eax, eax
    mov     ecx, 128
    mov     dword ptr [rbp - 4], 0
    mov     dword ptr [rbp - 8], 100
    mov     edx, dword ptr [rbp - 8]  # Start of modulo boilerplater
    mov     dword ptr [rbp - 20], eax 
    mov     eax, edx
    cdq
    idiv    ecx                       # Modulo CPU instruction
    mov     dword ptr [rbp - 12], edx # End of modulo sequence
    mov     ecx, dword ptr [rbp - 8]  # Start of shift boilerplate
    sar     ecx, 7                    # Shift CPU instruction
    mov     dword ptr [rbp - 16], ecx # End of shift sequence
    mov     ecx, dword ptr [rbp - 20]
    mov     eax, ecx
    pop     rbp
    ret