Removing non-breaking spaces from strings using Python

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By : ZaiMongMot

Date : January 02 2021, 06:48 AM

I hope this helps you . You don't have a unicode string, but a UTF-8 list of bytes (which are what strings are in Python 2.x).
Try

code :

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MVC Bundling breaking my calc CSS statements by removing spaces?

By : Julian Lawford

Date : March 29 2020, 07:55 AM

wish of those help This is an issue of the optimizer.
To avoid the miniffier to remove the whitespaces, group the affected element with parenthesis. That workarrounds the issue.

code :

margin-left: calc((50%) - 480px);

Removing non-breaking spaces?

By : Devin Thompson

Date : March 29 2020, 07:55 AM

This might help you Ok, finally I had found the problem !!!
Encoding of PDO is the problem...

code :

PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES \'UTF8\'')

Write numpy array of numpy strings while encoding and removing all empty spaces (Python)

By : Dániel Kulcsár

Date : March 29 2020, 07:55 AM

may help you . Starting with the array of strings from your previous question (and my answer):

code :

arr = np.array(['\tSTART\t  0\n',  '12345 ABCDEFG',  '1A 2B3C',  '\nEN D'])

In [1153]: astr=''.join(arr)
In [1154]: astr
Out[1154]: '\tSTART\t  0\n12345 ABCDEFG1A 2B3C\nE N D'

In [1155]: import re
In [1156]: re.sub('\s','',astr)
Out[1156]: 'START012345ABCDEFG1A2B3CEND'

In [1157]: print(arr)
['\tSTART\t  0\n' '12345 ABCDEFG' '1A 2B3C' '\nE N D']

In [1158]: print(arr.tolist())
['\tSTART\t  0\n', '12345 ABCDEFG', '1A 2B3C', '\nE N D']

In [1164]: bstr=''.join(arr).encode('unicode_escape')
In [1165]: bstr
Out[1165]: b'\\tSTART\\t  0\\n12345 ABCDEFG1A 2B3C\\nE N D'
In [1166]: re.sub(b'\s',b'',bstr)
Out[1166]: b'\\tSTART\\t0\\n12345ABCDEFG1A2B3C\\nEND'

In [1168]: re.sub('\s','',astr).encode('unicode_escape')
Out[1168]: b'START012345ABCDEFG1A2B3CEND'

In [1177]: re.sub(b'\s',b'',astr.encode())
Out[1177]: b'START012345ABCDEFG1A2B3CEND'

In [1180]: b''.join(astr.encode().split())
Out[1180]: b'START012345ABCDEFG1A2B3CEND'

In [1181]: b''.join(astr.encode('unicode_escape').split())
Out[1181]: b'\\tSTART\\t0\\n12345ABCDEFG1A2B3C\\nEND'

In [1183]: (''.join(astr.split())).encode()
Out[1183]: b'START012345ABCDEFG1A2B3CEND'

Applescript code breaking when removing trailing spaces

By : user2963067

Date : March 29 2020, 07:55 AM

wish help you to fix your issue It's much easier to get text ranges with text 1 thru -1 of newText where -1 is the last character. This avoids also all as text coercions.

code :

on stripSpaces(thisText)
    local newText
    local pos
    local tempText

    set newText to thisText

    set tempText to ""

    repeat while tempText ≠ newText
        set tempText to newText

        --remove spaces before extension name
        set pos to the offset of ". " in newText

        if pos > 0 then
            set newText to text 1 thru pos of newText & text (pos + 2) thru -1 of newText
        end if

        --remove spaces before extension
        set pos to the offset of " ." in newText

        if pos > 0 then
            set newText to text 1 thru (pos - 1) of newText & text (pos + 1) thru -1 of newText
        end if

        --remove leading spaces
        if first character of newText = space then
            set newText to text 2 thru -1 of newText
        end if

        --remove trailing spaces
        if last character of newText = space then
            set newText to text 1 thru -2 of newText
        end if
    end repeat

    return newText
end stripSpaces

log stripSpaces("   spa     .          nish  . txt  ")

use AppleScript version "2.4" -- Yosemite (10.10) or later
use framework "Foundation"

on stripSpaces(thisText)
    set nsText to current application's NSString's stringWithString:thisText
    return (nsText's stringByReplacingOccurrencesOfString:" " withString:"") as text
end stripSpaces

log stripSpaces("   spa     .          nish  . txt  ")