 Decrease WMI query execution time
By : Hiran Amarasinghe
Date : March 29 2020, 07:55 AM
help you fix your problem I would recommend querying only the properties you really need. So, if you only need the LicenseStatus value of the SoftwareLicensingProduct WMI class then use the following query: code :
SelectQuery searchQuery = new
SelectQuery("SELECT LicenseStatus FROM SoftwareLicensingProduct");
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 Decrease execution time of SQL query
By : Trushart
Date : March 29 2020, 07:55 AM
To fix this issue I've got a question in terms of processing and making a query more efficient whilst maintaining its accuracy. Before I display the query I'd like to point out some basics of it. , Your problem is this condition cant use INDEX code :
AND TF.readyforwork = CASE -- HERE IS THE PROBLEM
WHEN TF.trk_trackerstatus_lkid2 IS NULL THEN 0
ELSE 1
END
AND ( TF.readyforwork = 0 and TF.trk_trackerstatus_lkid2 IS NULL
OR TF.readyforwork = 1 and TF.trk_trackerstatus_lkid2 IS NOT NULL
)
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 How to loop numpy ndarray by using cupy? Is will really improve execution time?
By : Alan Rubin
Date : March 29 2020, 07:55 AM
it should still fix some issue You will experience a huge boost in performance if you vectorize the option with NumPy's built-in functions: code :
Array_B[array_A < 200] = -1000
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 How to increase or decrease a progress bar width within given time with pure JavaScript?
By : Hoang
Date : March 29 2020, 07:55 AM
hop of those help? I would recommend using requestAnimationFrame first. Next, use a timer instead of counting how many times it is called. I made a few minor adjustments (you can call it with a different number to have a different delay). RAF docs: https://developer.mozilla.org/en-US/docs/Web/API/window/requestAnimationFrame code :
function move(delay) {
var elem = document.getElementById("myBar");
var end = Date.now() + delay;
var frame = () => {
var timeleft = Math.max(0, end - Date.now());
elem.style.width = (100*timeleft)/delay + '%';
elem.innerHTML = (timeleft/1000).toFixed(1) + 's';
if (timeleft === 0) return;
requestAnimationFrame(frame);
};
requestAnimationFrame(frame);
}
#myProgress {
width: 100%;
background-color: #ddd;
}
#myBar {
width: 100%;
height: 30px;
background-color: #4CAF50;
text-align: center;
line-height: 30px;
color: white;
}
<!DOCTYPE html>
<html>
<body>
<div id="myProgress">
<div id="myBar">7.0s</div>
</div>
<br>
<button onclick="move(7000)">Start</button>
</body>
</html>
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How to rewrite double for loop in Numpy to save execution time?
By : Narayana Reddy Y
Date : March 29 2020, 07:55 AM
With these it helps Somebody beat me to it in the comments, but I have some timing information for you. Note that your times may vary, but relative times should be fairly representative of the performance you might see. First your code, which I fixed to make runnable: code :
cards = []
for figure in range(2, 15):
for suite in [1, 2, 3, 4]:
card = [figure, suite]
cards.append(card)
# 8.04 µs ± 27.5 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)
import numpy as np
cards = np.mgrid[1:5, 2:15]
# 20.5 µs ± 320 ns per loop (mean ± std. dev. of 7 runs, 10000 loops each)
import itertools as it
figures = range(2, 15)
suits = [1, 2, 3, 4]
cards = list(it.product(suits, figures))
# 2.5 µs ± 27.3 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)
cards_it = it.product(suits, figures) # notice no 'list'
# 479 ns ± 9.5 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
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code :
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