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Find next lower item in a sorted list


Find next lower item in a sorted list

By : TatikiN
Date : January 02 2021, 06:48 AM
help you fix your problem How about bisect?
code :


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How to find an index at which a new item can be inserted into sorted list and keep it sorted?

How to find an index at which a new item can be inserted into sorted list and keep it sorted?


By : Szocs Barni
Date : March 29 2020, 07:55 AM
Hope that helps Use bisect. It's not the most beautiful API, but it's exactly what you need.
You'll want to use bisect.bisect, which returns exactly what you want.
Find where an item belongs in a sorted list

Find where an item belongs in a sorted list


By : user2725536
Date : March 29 2020, 07:55 AM
will help you The most efficient way if the list is already sorted is to use binary search. Java has a built in binary search for collections you might be able to use:
code :
arraylist.add(Collections.binarySearch(arraylist, newString), newString)
Meteor UX Issue: After adding item to a sorted list, the item is added to the top and then sorted

Meteor UX Issue: After adding item to a sorted list, the item is added to the top and then sorted


By : Lucas
Date : March 29 2020, 07:55 AM
Hope this helps I figured out what was happening.
The problem in the end was a conflict with the sorting I was using and how the timestampable (https://atmospherejs.com/zimme/collection-timestampable) package adds the createdAt field.
Find Item lower or equal to value in list

Find Item lower or equal to value in list


By : Janaki
Date : March 29 2020, 07:55 AM
hop of those help? I have a sorted csv file with multiple columns and I want to return the value or the index of an item in column 1. This csv file has around 300.000 to 400.000 values so I'm trying to avoid any min function since it would propably take to long and I need the value in under a second. , This is assuming that you have a sorted list:
code :
def foo(the_list, value):
    index = bisect.bisect_left(the_list, value)
    return the_list[index] if the_list[index] == value or index == 0 else the_list[index-1]
Find the index of a item in a sorted list

Find the index of a item in a sorted list


By : Qamrain
Date : March 29 2020, 07:55 AM
I hope this helps . We have a generated list: , If digits of your number are ABC, then index is:
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