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In MIPS Assembly, how do I truncate to two decimal places if I have a floating point value X.YZDEF in a floating point r


In MIPS Assembly, how do I truncate to two decimal places if I have a floating point value X.YZDEF in a floating point r

By : user3862283
Date : November 22 2020, 07:01 PM
This might help you You may want to look and see if these links will help you.
http://en.wikipedia.org/wiki/MIPS_architecture#MIPS_Assembly_Language
code :


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Is SQL Server 'MONEY' data type a decimal floating point or binary floating point?

Is SQL Server 'MONEY' data type a decimal floating point or binary floating point?


By : SomeUser
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Neither. If it were an implementation of floating point it would be subject to the same inaccuracies as FLOAT and REAL types. See Floating Point on wikipedia.
MONEY is a fixed point type.
How to truncate a floating point number after a certain number of decimal places (no rounding)?

How to truncate a floating point number after a certain number of decimal places (no rounding)?


By : shark99
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , What you're looking for is truncation. This should work (at least for numbers that aren't terribly large):
code :
printf(".2f", ((int)(100 * var)) / 100.0);
std::trunc(100 * var) / 100     // no need for casts
Round / Truncate floating point numbers to N decimal places in Inno Setup Pascal Script

Round / Truncate floating point numbers to N decimal places in Inno Setup Pascal Script


By : Professr0S
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , If rounding is acceptable, an easy solution is using the Format function:
code :
var
  Height, Width: Integer;
  DivisionOfHeightWidthF: Single;
begin
  ...
  DivisionOfHeightWidthF := Single(Width) / Height;
  Log(Format('The Division Of Height and Width: %.2f', [DivisionOfHeightWidthF]));
end;
var
  Height, Width: Integer;
  DivisionOfHeightWidthF: Single;
  S: string;
  P: Integer;
begin
  ...
  DivisionOfHeightWidthF := Single(Width) / Height;
  S := FloatToStr(DivisionOfHeightWidthF);
  P := Pos('.', S);
  if P < Length(S) - 2 then
  begin
    SetLength(S, P + 2);
  end;
  Log(S);
end;
How to convert Decimal Floating-Point To 64-bit Hexadecimal using IEEE-754 Floating-Point convention

How to convert Decimal Floating-Point To 64-bit Hexadecimal using IEEE-754 Floating-Point convention


By : Parth Bhagat
Date : March 29 2020, 07:55 AM
Hope that helps If I understand your question correctly, you want to find the underlying binary representation of an IEEE 754 binary64-format floating-point number, and show that binary representation in hexadecimal.
For obtaining the underlying bits, the struct module is your friend. The struct.pack operation lets you interpret the 8 raw bytes underlying the binary64 representation as a (byte)string of length 8, and the struct.unpack operation will then let you re-interpret that string as a nonnegative integer (for example). Once you've got the integer, it's easy to find the hex representation. Here's a complete example for your data:
how to input floating point numbers in assembly language... and how to add subtract and multiply these floating point nu

how to input floating point numbers in assembly language... and how to add subtract and multiply these floating point nu


By : Bobbyandck
Date : March 29 2020, 07:55 AM
I wish this help you I'd suggest that you give Floating Point Assembly a good read first. You will unquestionably want to use the floating point instructions rather than the standard x86 instruction set if you are planning to do anything serious.
After reading the documentation your most likely questions will revolve around how the floating point values are represented and how to display them to a user. I'd suggest that you rework this question (if it doesn't get downvoted) or open a new one that is more specific. :)
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