minimum cost path through a cost matrix with positive and negative cost
By : Inez Jester
Date : March 29 2020, 07:55 AM
hope this fix your issue Let's say that H[i, j] is the minimum health the player needs when starting from square (i, j). We are interested in H[1, 1], which is the minimum health needed from the starting square. I assume that all values in the cost matrix M are integers. Therefore, the smallest positive health is 1. code :
H[m, n] = max(1  M[m, n], 1)
H[m, i] = max(H[m, i+1]  M[m, i], 1)
H[j, n] = max(H[j+1, n]  M[j, n], 1)
H[i, j] = min(max(H[i, j+1]  M[i, j], 1),
max(H[i+1, j]  M[i, j], 1))
int[] H = new int[m, n];
H[m, n] = max(1  M[m, n], 1);
// remember to loop backwards
for (int i = m1; i >= 1; i)
H[m, i] = max(H[m, i+1]  M[m, i], 1);
for (int j = n1; j >= 1; j)
H[j, n] = max(H[j+1, n]  M[j, n], 1);
// again, loop backwards
for (int i = m1; i >= 1; i)
for (int j = n1; j >= 1; j)
H[i, j] = min(max(H[i, j+1]  M[i, j], 1),
max(H[i+1, j]  M[i, j], 1));
return H[1, 1];

Difference among amortized cost, average cost, and expected cost
By : AXMT
Date : March 29 2020, 07:55 AM
hope this fix your issue Average cost of an algorithm is literally based on taking the average cost for each possible case the algorithm may work on, and dividing it by the number of said cases. If algorithm may work on 4 different inputs A,B,C,D in x, 2x, 3x, and 4x time, then it's average cost would be; code :
(x + 2x + 3x + 4x) / 4 = 2.5 * x.
(0.5 * x + 0.3 * 2x + 0.1 * 3x + 0.1 * 4x) = 1.8 * x.

Sql Server execution plan, cost of nonclustered index scan
By : Omar Kamal
Date : March 29 2020, 07:55 AM
this will help That depends on your query. The total query always costs 100%. So if you have a query like

How can I measure the cost of a database index?
By : user4387908
Date : March 29 2020, 07:55 AM
will be helpful for those in need I am actually going to disagree with Hexist. PostgreSQL's planner is pretty good, and it supports good sequential access to table files based on physical order scans, so indexes are not necessarily going to help. Additionally there are many cases where the planner has to pick an index. Additionally you are already creating primary keys for unique constraints and primary keys. I think one of the good default positions with PostgreSQL (MySQL btw is totally different!) is to wait until you need an index to add one and then only add the indexes you most clearly need. This is, however, just a starting point and it assumes either a lack of a general lack of experience in looking at query plans or a lack of understanding of where the application is likely to go. Having experience in these areas matters.

Why does this clustered index has more cost than the same nonclustered in sql server
By : jifegg
Date : March 29 2020, 07:55 AM
help you fix your problem For your test query, the index is a "covering" index, because it already contains all columns required for the result set. Therefore, no additional reads for the actual table are required. And because the index is smaller (less pages), the access is faster. The clustered index is actually the table itself, ordered by the index. Because it contains more columns, more page reads are required.

