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Moving a member of a List to the Front of the List


Moving a member of a List to the Front of the List

By : Flora9
Date : November 21 2020, 07:01 PM
may help you . The List class doesn't offer such a method, but you can write an extension method that gets the item, removes it and finally re-inserts it:
code :


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Moving a list of ints to the front of a list

Moving a list of ints to the front of a list


By : nicodom
Date : March 29 2020, 07:55 AM
This might help you I have a List of Int64 (List A) that needs to moved infront of another List (Int64) (List B). , Yo can try the following:
code :
var result = listA.Concat(listB.Except(listA)).ToList();
// Gives: 1, 4, 5, 9, 2, 10, 15, 14
Moving an object in list to the front of the list

Moving an object in list to the front of the list


By : Maha Salman
Date : March 29 2020, 07:55 AM
Does that help I don't know if there is an easier way to do it, but in the past when confronting this problem I did the following.
I added a nullable int to the database table, then I made a foreach loop and depending on whatever qualifications I wanted on top I gave a lower number. Then I did orderby.
code :
  @foreach (var c in Model.Cleaners)
 {
c.ConfirmationChecker = 1;
foreach (var p in c.TimeConfirmations)
{
    if (condition)
    {
        c.ConfirmationChecker = 0;
    }


}
}
  @foreach (var c in Model.Cleaners.OrderBy(x => x.ConfirmationChecker))
Python - reordering items in list by moving some items to the front while keeping the rest in the same order

Python - reordering items in list by moving some items to the front while keeping the rest in the same order


By : sandra
Date : March 29 2020, 07:55 AM
it fixes the issue I am trying to reorder items in a list in a way illustrated by the following example:
code :
def reorder_list(items, early):
    moved = [item for item in early if item in items]
    remain = [item for item in items if item not in moved]
    return moved + remain
def reorder_list(items, early):
    result = list(items)
    for move in reversed(early):
        try:
            place = result.index(move)
            result = [result[place]] + result[:place] + result[place+1:]
        except ValueError:
            pass   # this item wasn't in the list
Moving single member of an Object in List into an array for usew in a calculation

Moving single member of an Object in List into an array for usew in a calculation


By : Nayan
Date : March 29 2020, 07:55 AM
Any of those help I have a List of objects(Appliance as String and KwHHr as Double), applianceListReturn , in Visual Basic 2010. Each object has two members. I would like to take one member(KwHHr) of the same type from each object and make an array out of those single members. I am new to VB and this is not as easy as it first appeared. I have attempted to use a `for each loop to achieve this but it only returns one value. This is my code: , You can use LINQ to Object to achieve that:
Moving an element to the front of a list in Scala

Moving an element to the front of a list in Scala


By : akash singh
Date : March 29 2020, 07:55 AM
I hope this helps . I was wondering if there is a way to find an element in a list and move it to the front of the list in Scala? Is there any easy way to do this other than iterating over the list, then removing that element and then pre-pending it to the front of the list? , How about using span?:
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