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How many elements can be held in a B-tree of order n?


How many elements can be held in a B-tree of order n?

By : user3861749
Date : November 21 2020, 07:01 PM
it fixes the issue Terminology
The Order of a B-Tree is inconstantly defined in the literature.
code :


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B+ tree print elements is order

B+ tree print elements is order


By : Fl_img
Date : March 29 2020, 07:55 AM
around this issue Mark the nodes as you traverse them. Once the node is marked, it can't be traversed.
Tree elements not displaying in correct order

Tree elements not displaying in correct order


By : user3191147
Date : March 29 2020, 07:55 AM
like below fixes the issue I am trying to build a simple tree program and traverse it in inorder,preorder and postorder formats. The code I am using is this : , The tree structure you are ending up is something like below
code :
                    10
                      \
                       20
                     /
                   15
Grab IDs of all elements in DOM tree order on Submit

Grab IDs of all elements in DOM tree order on Submit


By : Peter Edworthy
Date : March 29 2020, 07:55 AM
This might help you I'm building a form on a page that has a drag-and-drop interface with jQuery UI's sortable, and it's being integrated in to Bootstrap 3's JavaScript Tabs. However, once the content is in the order I want it, and the form is submitted, I need to "loop through" all the relevant elements and submit them, in the DOM tree order, for a script to handle. , You can use jQuery's hasAttribute selector on an each loop:
code :
$("*[id]").each(function( index ) {

});
Tree Level-Order Traversal of Elements in a Vector

Tree Level-Order Traversal of Elements in a Vector


By : Vojtech Zoresan
Date : March 29 2020, 07:55 AM
seems to work fine (The solution that follows is written in Swift, but I hope you can follow it and translate to your favourite language of choice, in case you wish to make use of it)
code :
/* given 'arr', returns array expanded to full binary tree (if necessary) */
func expandToFullBinary(arr: [String], expandByCharacter: String = "*") -> [String] {

    let binLength = Int(pow(2.0,Double(Int(log2(Double(arr.count)))+1)))-1
    if arr.count == binLength {
        return arr
    }
    else {
        let diffLength = binLength - arr.count
        var arrExpanded = [String](count: binLength, repeatedValue: expandByCharacter)

        var j = 0
        for i in 0 ..< arr.count {
            if i < (arr.count - diffLength) {
                arrExpanded[i] = arr[i]
            }
            else {
                arrExpanded[i+j] = arr[i]
                j = j+1
            }
        }

        return arrExpanded
    }
}
/* assumes 'arr' describes a full binary tree */
func printFullBinaryTree(arr: [String]) {

    var posVectorA : [Int] = [arr.count/2]
    var posVectorB : [Int]
    var splitSize : Int = arr.count/2

    var elemCount = 0

    if arr.count < 2 {
        print("\(arr.first ?? "")")
    }
    else {
        while elemCount < arr.count {
            posVectorB = []
            splitSize = splitSize/2
            for i in posVectorA {

                if elemCount == arr.count {
                    print("noo")
                    break
                }

                print(arr[i], terminator: " ")
                elemCount = elemCount + 1

                posVectorB.append(i-splitSize-1)
                posVectorB.append(i+splitSize+1)
            }
            print("")
            posVectorA = posVectorB
        }
    }
}
/* Example */
var arrFullBinary : [String] = ["8", "4", "9", "2", "a", "5", "b", "1", "c", "6", "d", "3", "e", "7", "f"]

var arrNonFullBinary : [String] = ["g", "8", "h", "4", "i", "9", "j", "2", "a", "5", "b", "1", "c", "6", "d", "3", "e", "7", "f"]

printFullBinaryTree(expandToFullBinary(arrFullBinary, expandByCharacter: ""))
/* 1
   2 3
   4 5 6 7
   8 9 a b c d e f    */

printFullBinaryTree(expandToFullBinary(arrNonFullBinary, expandByCharacter: ""))
/* 1
   2 3
   4 5 6 7
   8 9 a b c d e f
   g h i j            */
Elements out of order in b-tree implementation

Elements out of order in b-tree implementation


By : basel zaid
Date : March 29 2020, 07:55 AM
To fix this issue I do believe that the problem is somewhere near the end of ArvoreBInsereNaoCheio:
code :
Pagina *f = x->c[i];
if(f->n == 2*a-1){ // Pagina cheia
    ArvoreBDivideFilho(x,i,f);
    if(k>x->keys[i])i++;
}
ArvoreBInsereNaoCheio(f,k);
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