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Copy method optimization in compilers


Copy method optimization in compilers

By : sak006
Date : November 21 2020, 07:01 PM
wish of those help This statement is copy-initialization of a Stack called copy from the return value of CopyStack(). There's no assignment.
code :


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Which, if any, C++ compilers do tail-recursion optimization?

Which, if any, C++ compilers do tail-recursion optimization?


By : Thie Le
Date : March 29 2020, 07:55 AM
wish of those help All current mainstream compilers perform tail call optimisation fairly well (and have done for more than a decade), even for mutually recursive calls such as:
code :
int bar(int, int);

int foo(int n, int acc) {
    return (n == 0) ? acc : bar(n - 1, acc + 2);
}

int bar(int n, int acc) {
    return (n == 0) ? acc : foo(n - 1, acc + 1);
}
What is Dynamic Optimization in compilers

What is Dynamic Optimization in compilers


By : user3200977
Date : March 29 2020, 07:55 AM
will help you Static optimization is based on the program code itself. Alternatively, dynamic optimization is based on code execution results. For example, having a long switch statement in C/C++, it would be possible to optimize it by changing case operators order. To do this, it is necessary to run the program many times and keep this switch operator statistics.
Some modern compilers contain such optimization framework, which allows to run the program and save its runtime statistics. Then the program code is optimized by using this statistics.
Possible optimization for compilers or defined behaviour

Possible optimization for compilers or defined behaviour


By : Fernando
Date : March 29 2020, 07:55 AM
like below fixes the issue The standard guarantees that reinterpret_cast used to convert from a pointer to a suitable integral type (large enough to hold all values) and back to the original pointer type is guaranteed to produce the same pointer value. So yes, this is guaranteed:
code :
int *p = new int(5);
intptr_t i = reinterpret_cast<intptr_t>(p);
// ...
int *q = reinterpret_cast<int*>(i);

assert(p == q);
*q = 10;
assert(*p == 5);
IL optimization for JIT compilers

IL optimization for JIT compilers


By : user3819437
Date : March 29 2020, 07:55 AM
around this issue The two patterns yo described are the easy stuff that the JIT actually gets right (except for non-primitive structs). In SSA form constant propagation and elimination of dead values is very easy. No, you have to test what the JIT can do. Look into compiler literature to see what standard optimizations to expect. Then, test for them. The two JITs that we have right now optimize very little and sometimes do not get the most basic stuff right. For example, MyStruct s; s.x = 1; s.x = 1; is not optimized by RyuJIT. s = s; isn't either. s.x + s.x loads x twice from memory. Expect little. You need to understand what machine code basic operations map to. This is not too complicated. Try a few things and look at the disassembly listing. You'll quickly get a feel for what the output is going to look like.
Why C++ compilers have many optimization levels

Why C++ compilers have many optimization levels


By : Fredy Daruwala
Date : March 29 2020, 07:55 AM
To fix the issue you can do Off the top of my head: optimizing takes time (more optimization means slower compilation), debugging optimized code can be more difficult, more aggressive optimization can reveal bugs, you can optimize for different things (program size, speed, etc.)…
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