sorl-thumbnail and file renaming

sorl-thumbnail and file renaming

By : user3861586
Date : November 20 2020, 07:00 PM
I hope this helps you . First part:
Just pass it in like this: sizes=( (56,34), (195,123), )
code :

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Django - sorl-thumbnail - accessing thumbnail image from view functions

Django - sorl-thumbnail - accessing thumbnail image from view functions

By : Ajit Panigrahi
Date : March 29 2020, 07:55 AM
it helps some times Tried using thumbnails_for_file() and all_thumbnails() inside sorl-thumbnail 3.2.5 utils.py, but was unsuccessful. Seemed like those functions were returning thumbnails that were parsed directly from django templates. It just didn't return all thumbnail files.
Ended up just parsing out the file path by
code :
Specifying file name and destination in get_thumbnail function of sorl thumbnail

Specifying file name and destination in get_thumbnail function of sorl thumbnail

By : Mihailo Tomić
Date : March 29 2020, 07:55 AM
it fixes the issue Short answer: you can't. The path and filename are generated by sorl and directly relate to how the thumbnail paths and their files are cached, and stored.
If you look at the actual method in sorl that gets or creates the thumbnail:
sorl-thumbnail: encoder error -2 when writing image file

sorl-thumbnail: encoder error -2 when writing image file

By : blackwingcat2000
Date : March 29 2020, 07:55 AM
Hope this helps I ended up patching the file pil_engine.py in /lib/python2.7/site-packages/sorl/thumbnail/engines:
code :
--- pil_engine.py   2013-09-09 03:58:27.000000000 +0000
+++ pil_engine_new.py   2013-11-05 21:19:15.053034383 +0000
@@ -79,6 +79,7 @@
             image.save(buf, **params)
         except IOError:
+            ImageFile.MAXBLOCK = image.size[0] * image.size[1]
             image.save(buf, **params)
         raw_data = buf.getvalue()
sorl-thumbnail: Creating a thumbnail inside a for loop in a template

sorl-thumbnail: Creating a thumbnail inside a for loop in a template

By : user3799622
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I am trying to create a thumbnail with the size of 100x100 px from an image. I am using a for loop, and the for loops works and the image is rendered but for some reason when I am trying to create a thumbnail it doesn't work. , It looks like your plural are in the wrong spot:
code :
{% for post_images in post.sellpostimage_set.all %}
{% for post_image in post.sellpostimage_set.all %}
post_image = SellPostImage.objects.filter(post=poster_posts)
context_dict['post_image'] = post_image
post_images = SellPostImage.objects.filter(post=poster_posts)
context_dict['post_images'] = post_images
post_image = SellPostImage.objects.get(post=poster_posts)
context_dict['post_image'] = post_image
{% for post_images in post.sellpostimage_set.all %}
<img class="thumbnail" src="{{ post_images.pictures.url }}" />
<img class="thumbnail" src="{{ post_image.picture.url }}" />
Renaming sorl-thumbnail images in templates

Renaming sorl-thumbnail images in templates

By : Hakingpawns
Date : March 29 2020, 07:55 AM
this one helps. Yes it is possible by creating your own backend based on the default one and overload the _get_thumbnail_filename method.
For example, something like this
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