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# Will a source-removal sort always return a maximal cycle?

By : Near-80
Date : November 20 2020, 07:00 PM
Hope this helps By source-removal I presume you mean at each step removing a node with no incoming edges.
What I think you are asking for is finding the maximal Euler tour of your graph (i.e. a cycle with unique edges, while nodes can be repeated).
code :

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## LINQ: Finding maximal element (not maximal value)

By : BRusinov
Date : March 29 2020, 07:55 AM
Jon Skeet has MaxBy in his MoreLINQ library: http://code.google.com/p/morelinq
code :
``````e.OrderByDescending(x => x.SomeProperty).First();
``````

## Maximal Spanning Tree to find a minimal set of edges that cover each cycle

By : Amechiajs
Date : March 29 2020, 07:55 AM
Index the arcs 1...m. Let j refer to arbitrary arc.

## Remove duplicate field by Max Order_id and sort by maximal

By : yuvaking96
Date : March 29 2020, 07:55 AM
wish of those help You can solve this by storing the data into an associative array keyed by nid values: if you do this in order of increasing Order_id you will be left with the most "recent" values per nid
If your data is in \$array:
code :
``````// Sort by Order_id
array_multisort(array_column(\$array, "Order_id"), \$array);
// Keep one entry per nid
foreach (\$array as \$row) {
\$hash[\$row["nid"]] = \$row;
}
// Convert back to indexed array:
\$result = array_values(\$hash);
``````

## how find a maximal set or a superset from a list of sets (Maximal set is the set which is not subset of another set in t

By : Karthick S
Date : March 29 2020, 07:55 AM
it should still fix some issue This is about finding dense communities in a graph based on density criteria and all the sets below are dense communities of a graph

## Purpose of maximal vs non-maximal implicit arguments

By : bala
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have just discovered the existence of maximal and non-maximal arguments (see https://coq.inria.fr/refman/Reference-Manual004.html#sec109). ,
... is there some motivation to use one over the other ?