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Python creating a dictionary and swapping these into another file


Python creating a dictionary and swapping these into another file

By : user3861255
Date : November 19 2020, 07:01 PM
it fixes the issue It looks like you could more usefully use the Python standard library csv module here. rather than perform the text processing parts youself "manually". E.g.:
code :


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creating dictionary within a dictionary in python reading some data is a csv file

creating dictionary within a dictionary in python reading some data is a csv file


By : mark
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have a csv file called sample.csv which contains the following data:- , A solution with csv module
code :
import dateutil.parser
import csv

data_dict = {}
with open('data.csv', 'r') as csvfile:
    csvreader = csv.reader(csvfile)
    for row in csvreader:
        dt = dateutil.parser.parse(row[0])
        if not data_dict.get(dt.hour,''):
            data_dict[dt.hour] = {}
        if not data_dict[dt.hour].get(dt.minute,''):
            data_dict[dt.hour][dt.minute]=[]
        data_dict[dt.hour][dt.minute].append(row[1:])
Creating a dictionary using python and a .txt file

Creating a dictionary using python and a .txt file


By : user2603125
Date : March 29 2020, 07:55 AM
wish helps you I have downloaded the following dictionary from Project Gutenberg http://www.gutenberg.org/cache/epub/29765/pg29765.txt (it is 25 MB so if you're on a slow connection avoid clicking the link) , Here is a function that returns the first definition:
code :
def lookup(word):
    word_upper = word.upper()
    found_word = False
    found_def = False
    defn = ''
    with open('dict.txt', 'r') as file:
        for line in file:
            l = line.strip()
            if not found_word and l == word_upper:
                found_word = True
            elif found_word and not found_def and l.startswith("Defn:"):
                found_def = True
                defn = l[6:]
            elif found_def and l != '':
                defn += ' ' + l
            elif found_def and l == '':
                return defn
    return False

print lookup('hallucination')
Creating dictionary from a file? Python

Creating dictionary from a file? Python


By : E.Gregg
Date : March 29 2020, 07:55 AM
With these it helps I am trying to store the contents of a file into a dictionary, and I thought I was doing it right, but It doesn't print out all of the contents, just the first line. I have no idea what I'm doing wrong, can anyone help me?
code :
def bringFile():
    moodFile = open("mood.txt",'r')
    moodread = moodFile.readlines()
    moodFile.close()
    return moodread

def makemyDict(theFile):
    moodDict = {}
    for lines in theFile:
        mood, name = lines.split(",")

        moodDict[mood] = name

    return (moodDict)
        #print the dictionary

        # for m in moodDict:
        #     return(m, name)
        # print(lines)

def main():

    moodFile = bringFile()
    Dict = makemyDict(moodFile)
    print(Dict)

main()
Creating *.mat file from Python without using dictionary

Creating *.mat file from Python without using dictionary


By : karthik
Date : March 29 2020, 07:55 AM
wish helps you I have few lists which i want to save it to a *.mat file. But according to scipy.io.savemat command documentation i Need to create a dictionary with the lists and then use the command to save it to a *.mat file. , How about
code :
scipy.io.savemat('interpolated_data_max_compare.mat', 
                 {'NA1_X_order10_ACCE_ms2': np.zeros((3000,1)),
                  'NA1_X_order10_DISP_mm': np.ones((3000,1))})
sio.savemat('...', data)
Python creating a dictionary from a csv file

Python creating a dictionary from a csv file


By : Ophilon
Date : March 29 2020, 07:55 AM
I wish did fix the issue. The problem is that, as the error message says, lists are not hashable, which means you can't use them as dict keys.
In fact, the reason lists aren't hashable is to prevent you from using them as dict keys. Lists are mutable, and if you mutate a key in a dict, lookup won't work anymore. (Technically, you could get around this by using a hash function based on object identity, instead of the contained values—but then either == wouldn't be useful, or it wouldn't line up with hash.)
code :
[[key, value] for ...]
[[tuple(key), value] for ...]
[[totalRank[0], 0] for ...]
lst = [[key, value] for ...]
dct = dict(lst)
dct = {key: value for ...}
dct2 = {tuple(rank): 0 for rank in totalRank}
dct2 = {rank[0]: 0 for rank in totalRank}
totalRank = []
for row in csv.reader(players):
    totalRank.append(row)
totalRank = list(csv.reader(players))
totalRank = [row[0] for row in csv.reader(players))
with open("mycsvfile.csv") as players:
    dict2 = {tuple(row): 0 for row in csv.reader(players)}
with open("mycsvfile.csv") as players:
    dict2 = {row[0]: 0 for row in csv.reader(players)}
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